CODEWITHSUNDEEP
scalaplayframework
Aiden
Aiden

Reputation: 355

List of Map to case Class scala

I have a router related data which is in following format:-

List(Map(routerId -> testR1, 
        config -> 
        List(
            Map(pin -> X12, color -> YELLOW), 
            Map(pin -> M20, color -> BLACK)
            )
        ),
    Map(routerId -> testR3,
        config -> 
        List(
            Map(pin -> M12, color -> YELLOW), 
            Map(pin -> X20, color -> BLACK),
            Map(pin -> M11, color -> RED)
            )
        )   

    )

and I have a Router case class 

case class Router(routerId: String, modelInfo: List[Map[String,String]])

I am trying to create a list of Router for which I tried cast using asInstanceOf somewhat like this: 

val data =  request.get("data").get.asInstanceOf[List[Map[String, List[Map[String, String]]]]]

But, I would prefer not to cast it if possible. Is there a better way to do this?

Edit: The request is actually the json request which looks like this:

{
    "data": [
            {
                "routerId": "testR1",
                "config": [
                    {
                        "pin": "X12",
                        "color": "Red"
                    },
                    {
                        "pin": "M15",
                        "color": "Yellow"
                    },
                    {
                        "pin": "X20",
                        "color": "Yellow"
                    }
                ]
            },
            {
                "routerId": "testR2",
                "config": [
                    {
                        "pin": "X20",
                        "color": "Black"
                    },
                    {
                        "pin": "M11",
                        "color": "Yellow"
                    }
                ]
            }
        ]
    }

I am using play 2 which is actually converting it to the List[Map...] format.

P.S. - I am a newbie to scala.

Upvotes: 1

Views: 427

Answers (1)

Stephen
Stephen

Reputation: 4296

You can use play-json like this ..

import play.api.libs.json._

implicit val reads = Json.reads[Router]

val jsResult: JsResult[Router] = Json.fromJson[Router](jsonString)

println(jsResult.get)

for more see

https://www.playframework.com/documentation/2.5.x/ScalaJson https://www.playframework.com/documentation/2.5.x/ScalaJsonAutomated

Upvotes: 1

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