Reputation: 1709
I have a grid composed with JLabel. Each cell has 3 states: public enum Token{ VIDE, CERCLE_ROUGE, CERCLE_BLEU } An empty cell == Token.VIDE
I have this simple algorithm that find all neighbors of a given cell then I use swing custom painting to draw a polygon following the path having the center of the label as points.
private CellsList getNeighbors(int row, int col) {
CellsList neighbors = new CellsList();
for (int colNum = col - 1 ; colNum <= (col + 1) ; colNum +=1 ) {
for (int rowNum = row - 1 ; rowNum <= (row + 1) ; rowNum +=1 ) {
if(!((colNum == col) && (rowNum == row))) {
if(withinGrid (rowNum, colNum ) ) {
neighbors.add( new int[] {rowNum, colNum});
}
}
}
}
return neighbors;
}
here is the condition to have a path:
if((size() >= MIN_PATH_LEGTH) && neighbors.contains(origin) ) {
add(cell);
return true;
}
Now I want to make it more precise by adding conditions such as a path can be valid if only there are at least 4 cells with the same value found in the neighborhood AND at least one opposite value.
Example: Red cells at (11, 10)(10, 11)(11, 12)(12, 11) can form a valid path if only there is at least a Blue cell at (11, 11). (See image below)
And the following can't be a valid path, so no drawing:
For now, the algorith finds a path only with the minimal value (int MIN_PATH_LEGTH = 3
) I've defined but I can't find a way to define the second condition (at least one opposite cell value within the neighborhood)
I'll edit with new elements if needed.
Upvotes: 1
Views: 834
Reputation: 18792
My answer is based on the code posted in a previous answer.
Path class
Add isWithinLoop
to check if a cell is within path by checking if it has a
path-cell to its left, right, top and bottom.
Also add getContainedWithin
which returns a collection of all cells that are bounded by the path, and their token is of the opposite color of the path
//returns a collection of all cells that are bounded by the path
//and their token is of the opposite color of the path
List<int[]> getContainedWithin() {
//find path max and min X values, max and min Y values
minPathRow = grid[0].length; //set min to the largest possible value
maxPathCol = grid.length;
maxPathRow = 0; //set max to the largest possible value
maxPathCol = 0;
//find the actual min max x y values of the path
for (int[] cell : this) {
minPathRow = Math.min(minPathRow, cell[0]);
minPathCol = Math.min(minPathCol, cell[1]);
maxPathRow = Math.max(maxPathRow, cell[0]);
maxPathCol = Math.max(maxPathCol, cell[1]);
}
//todo remove after testing
System.out.println("x range: "+minPathRow + "-"
+ maxPathRow + " y range: " + minPathCol + "-" + maxPathCol);
List<int[]> block = new ArrayList<>(25);
int[] cell = get(0);//get an arbitrary cell in the path
Token pathToken = grid[cell[0]][cell[1]]; //keep a reference to its token
//iterate over all cells within path x, y limits
for (int col = minPathCol; col < (maxPathCol); col++) {
for (int row = minPathRow; row < (maxPathRow); row++) {
//check cell color
Token token = grid[row][col];
if ((token == pathToken) || (token == Token.VIDE)) {
continue;
}
if (isWithinLoop(row,col)) {
block.add(new int[] {row, col});
}
}
}
return block;
}
//check if row, col represent a cell with in path by checking if it has a
//path-cell to its left, right, top and bottom
private boolean isWithinLoop(int row, int col) {
if( isPathCellOnLeft(row, col)
&&
isPathCellOnRight(row, col)
&&
isPathCellOnTop(row, col)
&&
isPathCellOnBottom(row, col)
) {
return true;
}
return false;
}
private boolean isPathCellOnLeft(int cellRow, int cellCol) {
for ( int col = minPathCol; col < cellCol ; col++) {
if(getPath().contains(new int[] {cellRow, col})) {
return true;
}
}
return false;
}
private boolean isPathCellOnRight(int cellRow, int cellCol) {
for ( int col = cellCol; col <= maxPathCol ; col++) {
if(getPath().contains(new int[] {cellRow, col})) {
return true;
}
}
return false;
}
private boolean isPathCellOnTop(int cellRow, int cellCol) {
for ( int row =minPathRow; row < cellRow ; row++) {
if(getPath().contains(new int[] {row, cellCol})) {
return true;
}
}
return false;
}
private boolean isPathCellOnBottom(int cellRow, int cellCol) {
for ( int row = cellRow; row <= maxPathRow; row++) {
if(getPath().contains(new int[] {row, cellCol})) {
return true;
}
}
return false;
}
}
Model class
Add a getter method to access getContainedWithin
:
List<int[]> getContainedWithin() {
return (path == null ) ? null : path.getContainedWithin();
}
Control class
Update ModelListener
to ignore a path if getContainedWithin
is empty:
private class ModelListener implements PropertyChangeListener {
@Override
public void propertyChange(PropertyChangeEvent evt) {
IndexedPropertyChangeEvent iEvt = (IndexedPropertyChangeEvent)evt;
int index = iEvt.getIndex();
int row = index / Model.COLS;
int col = index % Model.COLS;
Token token = (Token) evt.getNewValue();
SwingUtilities.invokeLater(new Runnable() {
@Override
public void run() {
view.setCell(token, row, col);
CellsList path = model.getPath();
//ignore path if null, empty or encloses no cell
if((path == null) || path.isEmpty()
|| model.getContainedWithin().isEmpty()) {
return;
}
view.addPath(path);
view.refresh();
}
});
}
}
The complete code can be downloaded for this repo.
Upvotes: 1
Reputation: 31
test before calling this method if the redCell's path OK:
public boolean isThereABlueCellWithinMyRedPath() {
// height = height of your map
// width = width of yout map
// this array is suppose to be in an other place...
Cell[][] cellArray = new Cell[height][width];
// ... so are those two lists
List<Cell> blueCellsList = new ArrayList<>();
List<Cell> redCellsList = new ArrayList<>();
//foreach blueCell on the map ...
for (Cell blueCell : blueCellsList) {
boolean north = false;
boolean east = false;
boolean south = false;
boolean west = false;
int originX = blueCell.getX();
int originY = blueCell.getY();
// ... if there is a redCell at north...
for (int i = originY; i >= 0; i--) {
if (redCellsList.contains(cellArray[originX][i])) {
north = true;
break;
}
}
// ... East ...
for (int i = originX; i < cellArray[originX].length; i++) {
if (redCellsList.contains(cellArray[i][originY])) {
east = true;
break;
}
}
// ... South ...
for (int i = originY; i < cellArray.length; i++) {
if (redCellsList.contains(cellArray[originX][i])) {
south = true;
break;
}
}
// ... West ...
for (int i = originX; i >= 0; i--) {
if (redCellsList.contains(cellArray[i][originY])) {
west = true;
break;
}
}
// ... I am surrended by redCell
if (south && east && north && west)
return true;
}
return false;
}
I did not try the code but it seems to work.
Upvotes: 2
Reputation: 31
Maybe you can make a list of blue cells and redcells and if you want to test if a there's a blue cell within the red cell's path you:
go to NORTH until you meet a redCell or a map limit : if it 's a map limit you test with the next blueCell, else you go back to your position and do the same for EAST, SOUTH, WEST. If on the 4 sides you find a redCell first, you return true else you return false.
It can be enough if you want to test in a quite small map. But if the shape made by the red cell can be free I don't find a better way.
Upvotes: 1