CODEWITHSUNDEEP
regex
Pranay
Pranay

Reputation: 578

Bash regular expression grep

So, I have a JSON array:

[ "3.22-SNAPSHOT_293022", "3.22-SNAPSHOT_296087",
"3.22-SNAPSHOT_latest", "3.22.1_293094", "3.22.1_296087",
"3.22.1_latest",, "3.23-SNAPSHOT_308024", "3.23-SNAPSHOT_308310", "3.23-SNAPSHOT_latest", "3.23.1_307802", "3.23.1_308022",
"3.23.1_latest", "4.0-SNAPSHOT_307842", "4.0-SNAPSHOT_307938",
"4.0-SNAPSHOT_308031", "4.0-SNAPSHOT_308193",
"4.0-SNAPSHOT_308308", "4.0-SNAPSHOT_308310", "latest" ]

First number indicates the version no. 2nd number indicates sub version number. I want to de-delect the items such that, a. 2 highest version numbers (which is not a snapshot) have 2 sub version left b. 2 highest version numbers (snapshot) have 2 sub version left c. rest versions have 1 subversion left.

Other entries can be deleted. Any point for the ways to do it would be great..

Upvotes: 0

Views: 42

Answers (1)

Ricardo Branco
Ricardo Branco

Reputation: 6079

Ways to do it:

  • Use bash regex combined with the -V (--version-sort) option of sort(1) and the jq utility to deal with JSON.
  • Use Python with the json module and the LooseVersion() function from distutils.version

I would opt for the latter... I'll leave the fun up to you until you request help with some code that you've tried.

Upvotes: 1

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