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javatomcatservlets
Some Name
Some Name

Reputation: 571

Tomcat Java Servlet path

I'm messing around with Maven/Tomcat/Java in Eclipse. I have made this java servlet, but when I go to localhost:xxxx/myapp/rest I don't get a response on my GET request, I get a 404. I thought if I put the @path to /rest I can send a GET request to the url, but it's not working. Does anyone know what the issue is? Thank you!

@Path("/rest")
public class WorldResource {
    @GET
    @Produces("application/json")
    public String getOrders() {
        WorldService service = ServiceProvider.getWorldService();
        JsonArrayBuilder jab = Json.createArrayBuilder();
        for (Country o : service.getAllCountries()) {
            JsonObjectBuilder job = Json.createObjectBuilder();
            job.add("iso2Code", o.getCode());
            job.add("iso3Code", o.getIso3Code());
            job.add("capital", o.getCapital());
            job.add("continent", o.getContinent());
            job.add("region", o.getRegion());
            job.add("surface", o.getSurface());
            job.add("population", o.getPopulation());
            job.add("government", o.getGovernment());
            job.add("latitude", o.getLatitude());
            job.add("longitude", o.getLongitude());
            jab.add(job);
        }
        JsonArray array = jab.build();
        System.out.println(array);
        return array.toString();

    }
}

Upvotes: 0

Views: 224

Answers (2)

Will Hartung
Will Hartung

Reputation: 118593

This is not a servlet, it's a JAX-RS Resource. This will not work "out of the box" within Tomcat, you'll need to deploy a JAX-RS implementation along with it (like Jersey).

A Servlet would look something like this:

@WebServlet(name = "WorldServlet", urlPatterns = {"/rest"})
public class WorldServlet extends HttpServlet {

    protected void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        response.setContentType("application/json");
        try (PrintWriter out = response.getWriter()) {
            ... // your code
            out.println(array.toString());
        }
    }
}

So, you really just need to look in to installing a JAX-RS provider. Also, when you do that, odds are high it STILL won't be at /rest, because the JAX-RS implementation is normally rooted at some path, so you might end up with something like /resources/rest.

That's all configurable of course.

Upvotes: 2

Simrandeep Singh
Simrandeep Singh

Reputation: 547

This can happen because your servlet is incapable of converting your POJO to appropriate HTTP response.

Instead of return array.toString();
try return Response.status(200).entity(array.toString()).build();

Upvotes: -1

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