CODEWITHSUNDEEP
pythonpython-3.x
mykill456
mykill456

Reputation: 91

How to set a timeout for Input

If you wait out the 4 seconds it says "You ran out of time" which is good. But then, to keep the loop going, you will have to press the enter key to continue.

I want so that when it prints "You ran out of time" underneath instead of just typing, that it displays an input statement like "Type 'attack' to keep going" and the loop would continue from where it was.

from threading import Timer
import time

monsterhp = int(800)
y = 150
while monsterhp > 0:
    timeout = 4
    t = Timer(timeout, print, ['You ran out of time.'])
    t.start()
    print(" ")
    prompt = "You have %d seconds Type 'attack' to hit the monster\nType here: " % timeout
    answer = input(prompt)
    t.cancel()

    if answer == "attack":
        print("You strike the monster")
        time.sleep(1)
        monsterhp = monsterhp - y
        print("War Lord Health:", monsterhp)

Upvotes: 7

Views: 9500

Answers (3)

Dipesh Paul
Dipesh Paul

Reputation: 487

import datetime

def custom_time_input(msg, seconds):
    try:
        print(msg)
        # current time in seconds
        current_time = datetime.datetime.now()
        time_after = current_time + datetime.timedelta(seconds=seconds)
        while datetime.datetime.now() < time_after:
            print("Time left: ", end="")
            print(time_after - datetime.datetime.now(), end="\r")
            time.sleep(1)
        print("\n")
        return True
    except KeyboardInterrupt:
        return False

res = custom_time_input("If you want to create a new config file PRESS CTRL+C within 20 seconds!", 20)
if res:
    pass # nothing changed
else:
    pass # do something because user pressed ctrl+c

> Blockquote

Upvotes: -2

sound wave
sound wave

Reputation: 3547

There is a new library inputimeout for standard input with timeout

$ pip install inputimeout

usage

from inputimeout import inputimeout, TimeoutOccurred
try:
    string = inputimeout(prompt='>>', timeout=5)
except TimeoutOccurred:
    string = 'time is over'
print(string)

Upvotes: 2

Taku
Taku

Reputation: 33764

Doing the task you proposed isn't as easy as you might've guessed. It is easier to use the signal module to do this: (I have incorporated your code with a modified version of the answer I linked)

import signal, time

def TimedInput(prompt='', timeout=20, timeoutmsg = None):
    def timeout_error(*_):
        raise TimeoutError
    signal.signal(signal.SIGALRM, timeout_error)
    signal.alarm(timeout)
    try:
        answer = input(prompt)
        signal.alarm(0)
        return answer
    except TimeoutError:   
        if timeoutmsg:
            print(timeoutmsg)
        signal.signal(signal.SIGALRM, signal.SIG_IGN)
        return None

monsterhp = int(800)
y = 150
while monsterhp > 0:
    timeout = 4
    timeoutmsg = 'You ran out of time.'
    print(" ")
    prompt = "You have %d seconds Type 'attack' to hit the monster\nType here: " % timeout
    answer = TimedInput(prompt, timeout, timeoutmsg)

    if answer == "attack":
        print("You strike the monster")
        time.sleep(1)
        monsterhp = monsterhp - y
        print("War Lord Health:", monsterhp)

Note: this will only work on all unix/mac system

You can change your while loop to this, for a improved version of your code:)

while monsterhp > 0:
        timeout = 4
        timeoutmsg = 'You ran out of time.'
        print(" ")
        prompt = "You have %d seconds Type 'attack' to hit the monster\nType here: " % timeout
        answer = TimedInput(prompt, timeout, timeoutmsg)

        if answer == "attack":
            print("You strike the monster")
            time.sleep(1)
            monsterhp = monsterhp - y
            print("War Lord Health:", monsterhp)
        elif answer == None:
            print("The War Lord has killed you, you're now dead")
            print("Thanks for playing, \nGAME OVER")
            break

Upvotes: 3

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