CODEWITHSUNDEEP
pythonpython-3.x
Jesús G
Jesús G

Reputation: 1

Compare tuple with list

planta_accesibles = probpl.RelacionRigida(
        lambda a1, p1, p2: (a1,(p1,p2))
                in [('A0', ('0', '1', '2', '3', '4'))]
        )

I want to search if p1 and p2 are included in my list 'A0', but python compare tuple "p1,p2" with tuple '0,1'. If I hold on " '2', '3', '4' " I don´t take a correct reponse.

Sorry for my english.

Upvotes: 0

Views: 84

Answers (1)

Aaron
Aaron

Reputation: 11075

I don't know what probpl.RelaciónRígida() is so I can't know what that needs, but I think I can sort of recognize what you're trying to do with the lambda function (feel free to correct me or ask questions).

It looks like you want to have a list named 'A0' and test if p1 and p2 are contained in it. In this case, I believe a dictionary would suit your needs better than a nested tuple:

ref = {"A0": ("0", "1", "2", "3", "4")}

This allows you to test the dictionary to determine if it contains a value (your tuple) associated with the key a1:

a1 in ref

After determining the dictionary contains an entry for a1, you can test whether that entry contains p1 and p2:

(p1 in ref[a1]) and (p2 in ref[a1]) #parenthesis are only added for readability

If I were to add this to your existing example it would look something like:

ref = {"A0": ("0", "1", "2", "3", "4")}
test = lambda a1, p1,p2: (a1 in ref) and (p1 in ref[a1]) and (p2 in ref[a1])
planta_accesibles = probpl.RelaciónRígida(test)

Upvotes: 1

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