CODEWITHSUNDEEP
javastring
codehacker
codehacker

Reputation: 401

Comparing 2 strings in Java

I have two Strings, for example:

s1=abcd
s2=abfg

I want to compare these two Strings and print the starting String until they are different. For instance, I want to print ab in this case. How can I get this result?

Upvotes: 1

Views: 128

Answers (3)

AnjuT
AnjuT

Reputation: 176

You can use substring(int startIndex, int endIndex) to split the strings from every position,

String s1 = "abcd";
String s2 = "abfg";
List<String> stringlist = new ArrayList<String>();

String shortest = null;
if(s1.length() <= s2.length()){
    shortest = s2;
}

for(int i = 1 ; i<shortest.length() ; i++){
    if(s1.substring(0,i).equals(s2.substring(0,i))){
        stringlist.add(s1.substring(0,i));
    }
}

System.out.println(stringlist.get(stringlist.size()-1));

Upvotes: 0

Achyuth23
Achyuth23

Reputation: 411

As @IvanPronin mentioned, If you do this very frequently you can use the indexOfDifference of StringUtils:

String s1 = "abcf";
String s2 = "abdf";
System.out.println(s1.substring(0, StringUtils.indexOfDifference(s1, s2)));

but you have to download the jar and include it. Download link

Upvotes: 1

pragadez
pragadez

Reputation: 89

package simple;

public class Simple {

    public static void main(String[] args) {
        String s1 = "abcf";
        String s2 = "abdf";
        StringBuilder sb = new StringBuilder();

        int k = s1.length() < s2.length() ? s1.length() : s2.length();

        for (int i = 0; i < k; i++) {
            if (s1.charAt(i) == s2.charAt(i)) {
                sb.append(s1.charAt(i));
            } else {
                break;
            }
        }
        System.out.print(sb);
    }
}

Upvotes: 1

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