CODEWITHSUNDEEP
regexregex-lookaroundslookbehind
user7579544
user7579544

Reputation:

Regex match digits with lookahead

I have a regex:

(\d{1,20})

Which matches:

JPY;       7112630;

In this string I want to catch only the digits: so I use: $1 But I also want to add ".00" after the digits so I use: $1.00

But now I also want to match the digits, only if I have JPY before.

I tried:

(?=JPY;\s*)(\d{1,20})
(?<=JPY;\s*)(\d{1,20})

No success!

Upvotes: 1

Views: 586

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626903

You may use a capturing group instead of the infinite-width positive lookbehind:

(JPY;\s*\d{1,20})

And replace with $1.00. See the regex demo.

Depending on the regex engine, you may remove the (...) capturing parentheses, and use $0 or $& instead of the $1 in the replacement pattern.

Also, if you need to match these values as whole words, enclose with word boundaries: \b(JPY;\s*\d{1,20})\b.

Upvotes: 1

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