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Pixeluz
Pixeluz

Reputation: 267

How to order a stacked barplot in R?

I couldn't find the answer to this problem, so I'm posting it.

I have a stacked barplot that I use to compare the occurrence of different values in my data

Now, I would like to order it in a decreasing order, starting with the biggest combined value. I tried using the method I use for normal barplots:

barplot(combined[order(combined, decreasing = T)],
    horiz = T,
    las=1,
    xlim = c(0,60),
    col = c('lightblue','darkblue'))

but it produces a barplot that is no longer stacked

Is there a way to order it properly? I've seen some solutions with ggplot, but I'd prefer sticking to standard barplots, if it's possible.

Thanks!

Upvotes: 1

Views: 528

Answers (2)

parth
parth

Reputation: 1631

I'm using the following example to explain the method 

num <- c(1, 8, 4, 3, 6, 7, 5, 2, 11, 3)
cat <- c(letters[1:10])
data <- data.frame(num, cat)

Now, to generate barplot in decreasing order

barplot(data[order(data[,1],decreasing=FALSE),][,1],names.arg=data[order(data[,1],decreasing=FALSE),][,2], horiz = TRUE)

enter image description here

Hope this example helps.

Upvotes: 1

Lu&#237;s Telles
Lu&#237;s Telles

Reputation: 694

Your problem is that you're using a matrix inside barplot() function. When you use order and compute combined[order(combined, decreasing=T)] the result is a vector. If you want to order your columns with no regard to which color would have precedence you may use this code:

barplot(combined[,order(apply(combined, 2, max))])

What this does is to apply the function max() on the columns (margin 2, margin 1 would be rows) of your matrix. Then you'll have a matrix ordered by the maximum value of each column.

Upvotes: 2

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