CODEWITHSUNDEEP
pythondjangodictionary
mahyard
mahyard

Reputation: 1248

How to extract items out of a QueryDict which contains keys with more than one value?

I have this QueryDict:

>>> from django.http import QueryDict
>>> q = QueryDict('a=1&a=2&c=3')

I need a piece of code which returns this result:

{ u'a': [u'1',u'2'], u'c': u'3'}

I should inform you that dict(q.iterlists()) returns this:

{ u'a': [u'1', u'2'], u'c': [u'3']}

Regards,

Upvotes: 0

Views: 702

Answers (3)

albar
albar

Reputation: 3100

Shorter answer:

{
   key:val if len(val)>1 else val[0]
   for key,val in q.lists()
}

Upvotes: 2

timgeb
timgeb

Reputation: 78760

I agree with the comments that you should not want this.

Anyway, this comprehension gets rid of the unicode strings (again, you should not want this) and single value lists:

d = { 'a': ['1', '2'], 'c': [u'3']}
>>> {k:(map(str, v) if len(v) > 1 else str(v[0])) for k,v in d.items()}
{'a': ['1', '2'], 'c': '3'}

Upvotes: 1

zaidfazil
zaidfazil

Reputation: 9235

If you want the querydict to be converted into json,

You could do something like this,

>>> from django.http import QueryDict
>>> q = QueryDict('a=1&a=2&c=3')
>>> q
<QueryDict: {'c': ['3'], 'a': ['1', '2']}>

I actually did it like this,

>>> string_dict = json.loads(json.dumps(dict(q)))
>>> string_dict
{'c': ['3'], 'a': ['1', '2']}

>>> for item in string_dict:
...     if len(string_dict[item]) == 1:
...         string_dict[item] = string_dict[item][0]
... 
>>> string_dict
{'c': '3', 'a': ['1', '2']}

Upvotes: 1

Related Questions