Reputation: 87
So I'm trying to figure out the best way to get this to work. I have a long list of code that's pulling off of a JSON database, and I'm trying to streamline it. I've created the following function:
var insertData = function(formattedData, originalData, referencePoint, insertPoint, insertStyle) {
var formattedData = originalData.replace("%data%", referencePoint);
$(insertPoint).insertStyle(formattedData);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js">
</script>
Is it possible to define a dot function similar to how I have it here - referenced as one of the function's variables? This current code says that insertStyle
is not a function - how do I get the code to recognize that insertStyle
should be taking a variable name? As in, if my fifth variable called by insertData
is append, it should be read as .append
.
As a reference, here's how I'm calling the function:
insertData("formattedHeaderName", "HTMLheaderName", bio.name, "#header", "prepend");
Thanks for any assistance or thoughts in advance!
Upvotes: 1
Views: 52
Reputation: 33933
When you pass an argument to a function, like you do in:
insertData("formattedHeaderName", "HTMLheaderName", bio.name, "#header", "prepend");
Those arguments are strings. Not jQuery methods.
So, a solution would be to define all the methods you need to use...
And just compare the string passed to decide.
var insertData = function(formattedData, originalData, referencePoint, insertPoint, insertStyle) {
var formattedData = originalData.replace("%data%", referencePoint);
if(insertStyle=="prepend"){
$(insertPoint).prepend(formattedData);
}
if(insertStyle=="append"){
$(insertPoint).append(formattedData);
}
if(insertStyle=="after"){
$(insertPoint).after(formattedData);
}
// And so on...
}
Maybe there is some other ways to achive this...
But this one is quick and easy to implement.
Upvotes: 0
Reputation: 46183
You're looking for a computed property:
$(insertPoint)[insertStyle](formattedData);
Basically, every property access can be represented as a computed property:
foo["bar"]; // same as foo.bar
In your original code, you're using a non-computed property so the interpreter looks for a method literally called "insertStyle", which doesn't exist.
Upvotes: 1