Reputation: 15692
I'm new to Rust and have been trying to wrap my head around this for three hours and I think I'm going insane. All I want is a parser that takes the string "true"
and returns an enum Value::Const(true)
. This is what I have so far:
// parser.rs
use nom::*;
#[derive(PartialEq, Debug, Clone)]
pub enum Value {
Const(bool),
}
fn true_value<T>(_: T) -> Value { Value::Const(true) }
fn false_value<T>(_: T) -> Value { Value::Const(false) }
named!(literal_true<&[u8]>, map_res!(tag!("true"), true_value));
named!(literal_false<&[u8]>, map_res!(tag!("false"), false_value));
But what I get is:
error[E0308]: mismatched types
--> src/parser.rs:25:1
|
25 | named!(literal_true<&[u8], Result<Value, String>>, map_res!(tag!("true"), true_value));
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ expected enum `parser::Value`, found enum `std::result::Result`
|
= note: expected type `parser::Value`
found type `std::result::Result<_, _>`
= note: this error originates in a macro outside of the current crate
I have no idea what is happening here. I tried to find examples or tutorials to get just a tiny hint on how to do this, but for some reason, this must be some rare edge thing nobody else tried to do before.
Upvotes: 1
Views: 1621
Reputation: 733
You have two issues: the function you pass to map_res
(as in map result) must return a Result
, and the function signature you pass to named
must indicate input and output types. If you don't want to return a result, you can use the map
macro
#[derive(PartialEq, Debug, Clone)]
pub enum Value {
Const(bool),
}
fn true_value<T>(_: T) -> Value { Value::Const(true) }
fn false_value<T>(_: T) -> Value { Value::Const(false) }
// input type and output type
named!(literal_true<&[u8], Value>, map!(tag!("true"), true_value));
// input type can be omitted if it's &[u8]
named!(literal_false<Value>, map!(tag!("false"), false_value));
Upvotes: 4