CODEWITHSUNDEEP
djangopython-3.x
Bob
Bob

Reputation: 8714

Django time convert format

I am trying to convert time into specific format using following code:

datetime.datetime.strptime(timezone.now() + timedelta(days=14), '%Y-%m-%dT%H:%M:%S.%f%z')

I am getting error that the first parameter has to be string.

I also tried using this code

datetime.datetime.strptime(str(timezone.now() + timedelta(days=14)), '%Y-%m-%dT%H:%M:%S.%f%z')

But then I am getting following error:

time data '2017-06-04 14:26:18.941458+00:00' does not match format '%Y-%m-%dT%H:%M:%S.%f%z'

Can someone suggest how can I convert to the specific format. Thanks!

Upvotes: 2

Views: 566

Answers (2)

zaidfazil
zaidfazil

Reputation: 9235

If you are trying to convert the datetime.datetime() object into string, you could just do this,

>>> datetime.datetime.strftime(timezone.now() + timedelta(days=14), '%Y-%m-%dT%H:%M:%S.%f%z')
'2017-06-04T14:45:23.621658+0000'

Or if you want it as the datetime object,

>>> datetime.datetime.strptime(str(timezone.now() + timedelta(days=14))[:26], '%Y-%m-%d %H:%M:%S.%f')
datetime.datetime(2017, 6, 4, 14, 50, 26, 5649)

Upvotes: 1

Garrett Kadillak
Garrett Kadillak

Reputation: 1074

Django has a built in date parser that abstracts the logic of strftime away called parse_datetime. You can simply pass in a date string and it will return a datetime.datetime object. Here's what your code would look like:

from django.utils.dateparse import parse_datetime
parse_datetime(str(timezone.now() + timedelta(days=14)))
>>> datetime.datetime(2017, 6, 4, 7, 45, 28, 301957)

Upvotes: 1

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