CODEWITHSUNDEEP
python
Kajal Bonde
Kajal Bonde

Reputation: 1

error getting while iterating over two lists in python

I am trying to run the code

list = ["ABCD", "LMN" , "STU" , "PQRS" ]

dict = ["ABCD" , "LMN" , "PQRS" ]

for i in list:
 for j in dict:
  if (i == j):
    print(i,j)
  else:
    print(i,j,"No match")

Expected output is,

ABCD ABCD
LMN LMN
STU No match
PQRS PQRS

But as it is comparing i with each value of j , Its giving me output as,

('ABCD', 'ABCD')
('ABCD', 'LMN', 'No match')
('ABCD', 'PQRS', 'No match')
('LMN', 'ABCD', 'No match')
('LMN', 'LMN')
('LMN', 'PQRS', 'No match')
('STU', 'ABCD', 'No match')
('STU', 'LMN', 'No match')
('STU', 'PQRS', 'No match')
('PQRS', 'ABCD', 'No match')
('PQRS', 'LMN', 'No match')
('PQRS', 'PQRS')

i tried with break and continue statements still not getting expected result Can anybody help me with this?

Upvotes: 0

Views: 35

Answers (3)

Rao
Rao

Reputation: 125

you can do with filter like this

results = list(filter(lambda x: x in dict,list))

Upvotes: 0

Kershaw
Kershaw

Reputation: 561

Seems like you are getting tuples instead of strings you hoped. Remove the parenthesis after print then you will get what you want.

print(i,j) =>print i,j

You got twice the expected output because your for loops check every element in the lists twice.

An easier way other than mentioned in the other answer is to use set module.

A =set(["1","2",.....])
B =set(["2","3",.....])
set.intersection(A,B)

BTW, avoid using list as your variable name. That is a preserved word.

Upvotes: 1

DMe
DMe

Reputation: 7826

You have a nested for loop - as such, you will compare each i in list with every single j in dict.

You could try the following instead:

for i in list:
    if i in dict: # checks if the string exists in dict. 
        print(i, i)
    else:
        print(i, "No match")

Upvotes: 2

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