CODEWITHSUNDEEP
pythonpython-3.xdictionary
jef
jef

Reputation: 4083

Create unique key list from dictionary array in one-line

I have a code like below. Although it works, I want to know more compact implementation. Is it possible to implement this code as one or two liners?

all_keys = []
dic_list = [{'apple': None, 'banana': None}, {'grape': 1, 'apple':None}]
for d in dic_list:
    for k in d.keys():
        if k not in all_keys: all_keys.append(k)
print(all_keys) # ['apple', 'banana', 'grape'] all unique keys

Upvotes: 0

Views: 86

Answers (4)

Hari Palappetty
Hari Palappetty

Reputation: 549

From the question, my inference is a shorter implementation which prints the keys in sorted manner.

dic_list = [{'apple': None, 'banana': None}, {'grape': 1, 'apple':2}]
all_keys = sorted({k for d in dic_list for k in d.keys()})
print(all_keys)

We can use python's powerful List/Set/Dictionary comprehensions to achieve this with relatively fewer lines of code.

Hope this helps.

Upvotes: 0

Arya McCarthy
Arya McCarthy

Reputation: 8829

You could use a set (marked by curly braces {}), which enforces that elements are not repeated:

all_keys = {k for d in dic_list for k in d.keys()}
# {'apple', 'banana', 'grape'}

This strategy is more efficient than looping, and the intent is much clearer.

Upvotes: 1

donkopotamus
donkopotamus

Reputation: 23176

Simply use set.union across the dictionaries:

>>> set().union(*dic_list)
{'apple', 'banana', 'grape'}

This approach is much faster than a double loop (such as set( val for dic in dic_list for val in dic.keys())))

Upvotes: 3

moritzg
moritzg

Reputation: 4396

This should do what you want:

list(set( val for dic in dic_list for val in dic.keys()))

Output:

['grape', 'apple', 'banana']

Upvotes: 2

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