CODEWITHSUNDEEP
javascriptjqueryjsonajaxasp.net-mvc
nik
nik

Reputation: 564

Return Json data to Ajax call

I have a method in MVC that I post to it and I need to return some data back to process. This is my MVC method that I post to and return Value is a json data.

[HttpPost]
public JsonResult GetCalculateAmortizationSchedule()
{
    var data = ...
    var httpClient = new HttpClient();
    var response = httpClient.PostAsJsonAsync("http://localhost:62815/v1/APR/CalculateAmortizationSchedule", data).Result;
    var returnValue = response.Content.ReadAsAsync<Dictionary<int, AmItem>>().Result;
    return Json(returnValue);
}

This is my AJax call that successfully run the MVC method. 

$('#MyForm').submit(function (e) {
    debugger;
    $.ajax({
        url: "/home/GetCalculateAmortizationSchedule",
        type: "POST",
        dataType: "json",
        contentType: "application/json; charset=utf-8",                
        success: function (result) {
            alert("success");
        },
        error: function (result) {
            alert("error");
        }
    });
    e.preventDefault();
});

My problem is how to catch the return value from method? when I run this after return Json(returnValue) the value is not returning to Ajax method and instead of seeing the Success Alert I see the error Alert.

Upvotes: 3

Views: 26901

Answers (3)

Allen King
Allen King

Reputation: 2506

Try this:

     success: function (result) {alert(JSON.stringify(result)); }

From the error you have posted in comments below, it appears Dictionary is not serializable. Try setting AllowGet as mentioned in other answers. If doesn't work, you will need to convert Dictionary to some other object that is serializable. Or you may follow this to serialize Dictionary to json in your controller.

How do I convert a dictionary to a JSON String in C#?

Upvotes: 3

Abhay
Abhay

Reputation: 47

Try this piece of code :

 return Json(returnValues, JsonRequestBehavior.AllowGet);

Upvotes: 1

Rahul
Rahul

Reputation: 448

You should add JsonBehavious if you are not getting values.

return Json(returnValue, JsonRequestBehavior.AllowGet);

Upvotes: 1

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