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DenCowboy
DenCowboy

Reputation: 15076

Take specific number from output

This is the output of some svn log command of me

------------------------------------------------------------------------
r23327 | xxx | 201x-0x-1x 15:09:20 +0200 (Mon, x x x) | 1 line
Changed paths:
   A /line/tags/1.1.1.1 (from /line/branches/uat:23326)

I want to grep or sed the nummber 23327 out of the output. Someone who can help me? I want it to work too with other numbers but same layout.

I tried something like

txt | grep '^r'
r23327 | xxx | 2017-05-15 15:09:20 +0200 (Mon, 15 May 2017) | 1 line

But I need to get rid of the 'r' and stop before the space before |

Upvotes: 1

Views: 23

Answers (1)

RomanPerekhrest
RomanPerekhrest

Reputation: 92854

sed approach:

sed -n 's/^r\([[:digit:]]*\) .*/\1/gp' file

The output:

23327

\([[:digit:]]*\) - captured group for digits preceded by r

Or with grep (PCRE):

grep -Po '^r\K[0-9]+ ' file

-P - allows PCRE

\K - ignores matches till the current position (i.e. ignore r before digits)

Upvotes: 1

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