CODEWITHSUNDEEP
pythonpython-2.7url
Álvaro Méndez Civieta
Álvaro Méndez Civieta

Reputation: 727

How to retrieve key value pairs from URL using python

I am working on a python 2.7 script such that given an URL with certain number of key-value pairs (not fixed numer of them), retrieves this values on a json structure.

This is what I have done so far:

from furl import furl

url = "https://search/address?size=10&city=Madrid&offer_type=1&query=Gran%20v"

f = furl(url) 
fields = ['size', 'city', 'offer_type', 'query']

l = []
l.append(f.args['size'])
l.append(f.args['city'])
l.append(f.args['offer_type'])
l.append(f.args['query'])

body = {
        fields[0]: f.args[fields[0]],
        fields[1]: f.args[fields[1]],
        fields[2]: f.args[fields[2]],
        fields[3]: f.args[fields[3]]
    }

This code works, but just for the case in which I know that there will be 4 key-value pairs, and the names of those pairs. I do not know how to face the problem if, for example, my url is shorter or larger.

Using this command length = len(f.args) I can obtain the number of pairs, but no idea of how to extract the key names from the f.args object

Thank you very much, Álvaro

Upvotes: 2

Views: 2036

Answers (3)

Mad Physicist
Mad Physicist

Reputation: 114440

The furl library is not especially well documented, but digging through the source code shows that f.args is a property that redirects eventually to an orderedmultidict.omdict object. This supports all the standard dictionary methods, in addition to lots more interesting stuff (also not well documented).

You can therefore just use f.args wherever you need body. If you need a copy for some reason, do f.args.copy(), or possibly dict(f.args).

Upvotes: 1

Jared Goguen
Jared Goguen

Reputation: 9010

I'm slightly confused... f.args is already a dictionary-like object of the type you want. If you want to explicitly convert it to a dictionary, you can use:

body = dict(f.args)

But even this seems unnecessary. If you want a new copy of the object so that you can change it without affecting the original instance, you can call the .copy() method.

Upvotes: 4

T.Salvin
T.Salvin

Reputation: 261

is this what you're looking for?

from furl import furl

url = "https://search/address?size=10&city=Madrid&offer_type=1&query=Gran%20v"

f = furl(url) 

print zip(f.args.keys(),f.args.values())

Output:

[('size', '10'), ('city', 'Madrid'), ('offer_type', '1'), ('query', 'Gran v')]

Upvotes: 2

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