CODEWITHSUNDEEP
javaexception
java
java

Reputation: 21

Does Java support resuming program execution after an exception?

i would like to know how an error can be caught in java but allow the program to continue to run.

here is my example:

public class test1 {
    public static void main(String[] args) {
        String str = new String("abcdefghij");
        try {
            System.out.println(str.charAt(0));
            System.out.println(str.charAt(9));
            System.out.println(str.charAt(10));
            System.out.println("is it still running");
        } catch (Exception e) {
            System.out.println("the index is out of bounds");
        }
    }
}

the following is printed:

a
j
the index is out of bounds

but after the error is thrown i would like the code to continue to run so that this is printed:

a
j
the index is out of bounds
is it still running

thanks in advance

Upvotes: 2

Views: 687

Answers (2)

user166390
user166390

Reputation:

Java does not support 'resuming' or 'restarting' after an exception.

You can wrap the specific line "to skip" in a try/catch (would be 3 total in the above example, one for each access) or, perhaps better, write code that will not throw an exception -- exceptions really ought to be "exceptional" IMOHO. You could also move the try/catch code into a method to "wrap" the access (e.g. call the method 3x), but the actions are the same.

Upvotes: 7

rxx
rxx

Reputation: 764

for(int i =0; i < Short.MAX_VALUE; i++){
 try{
    System.out.println(str.charAt(i));
 }catch(Exception ex){}
}

Also you can use finally bolck if you wish to execute always.

Upvotes: 2

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