CODEWITHSUNDEEP
javascript
four-eyes
four-eyes

Reputation: 12509

Currying returns "... is not a function"

I try to curry a function, which I define in a class someClass like this:

class SomeClass extends AnotherClass {

   _someFunc(arg1) {
        const foo = arg1.map(bar => {
            return function(arg2) {
                bar[arg2];
            }
        });

        return foo;
    }

   yetAnotherMethod() {
      ...
      somenewFunc()
   }

    someMethod()
        ...
        const someNewFunc = this._someFunc(someVar)("abc");
        ....

 }

In the same class, I have a method someMethod() where I try to calll my

When I start my App I get

this._someFunc(...) is not a function

Why is that?

Upvotes: 0

Views: 87

Answers (1)

Jonas Wilms
Jonas Wilms

Reputation: 138567

You may do:

const someNewFunc = this._someFunc(someVar)[0]("abc");

SomeFunc returns an Array. This will take the first function out of that array and calls it. If you want to get all values in an array, may do:

   _someFunc(arg1,arg2) {
    return arg1.map(bar =>bar[arg2]);
  }

const someNewFunc = this._someFunc(someVar,"abc");

Or if you want it to be a function:

_someFunc(arg1) {
 return function(arg2){
    return arg1.map(bar =>bar[arg2]);
 }
}

const someNewFunc = this._someFunc(someVar)("abc");

Upvotes: 1

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