CODEWITHSUNDEEP
bashshellsorting
CarlinLiu
CarlinLiu

Reputation: 33

Bash Script sorting array of files by size

I want to sort the files in my directory by their size. Currently I have found all the files with a certain extension (ie)*.txt) and then added all the values from that list into my unsorted array. I try to sort all the elements in my array by size, but the "-S" on the last line gives me an error.

list=$(find . -name "*."$1)
unsortedA=()
for x in $list
do
    unsortedA+=($x)
done

sortedA=( $(for arr in "${unsortedA[@]}" 
do
        echo $arr
done | sort -S) ) #This Line Here*

EDIT: All of these lines can be replaced with:

list=$(ls -S *.$1)

Upvotes: 3

Views: 924

Answers (1)

rici
rici

Reputation: 241701

Normally, sorting file listings by size is done with: 

ls -lS *.$1

In any case, sort -S is meaningless. -S is an option for ls; it means something else to sort. (And that something else is completely irrelevant here.)

If you want just the list of filenames, sorted by filesize, use

ls -S *.$1

and pipe it into whatever you want to use for formatting.

Upvotes: 3

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