Reputation: 65
I started using R today, so I apologize if this is too basic.
First I construct 2 matrices, and construct a vector, whose entries are these matrices. Then, I try to loop over the elements of the vector, i.e. the matrices. However, when I do, I get a "argument of length zero" error.
cam <- 1:12
ped <- 13:24
dim(cam) <- c(3,4)
dim(ped) <- c(4,3)
mats <- c('cam','ped')
for (i in 1:2) {
rownames(mats[i]) <- LETTERS[1:dim(mats[i])[1]]
colnames(mats[i]) <- LETTERS[1:dim(mats[i])[2]]
}
The error text is as follows:
Error in 1:dim(mats[i])[1] : argument of length 0
The question: how to loop over elements of a vector, these elements being matrices? (I'm guessing I'm not calling the elements correctly). Thank you for patience.
Upvotes: 0
Views: 77
Reputation: 3194
The go-to option in R is to use lists:
cam <- 1:12 ; dim(cam) <- c(3,4)
# same as matrix(1:12, nrow = 3, ncol = 4)
ped <- 13:24 ; dim(ped) <- c(4,3)
# save the list ( '=' sign for naming purposes only here)
mats <- list(cam = cam, ped = ped)
# notice the double brackets '[[' which is used for picking the list
for (i in 1:length(mats) {
rownames(mats[[i]]) <- LETTERS[1:dim(mats[[i]])[1]]
colnames(mats[[i]]) <- LETTERS[1:dim(mats[[i]])[2]]
}
# finally you can call the whole list at once as follows:
mats
# or seperately using $ or [[
mats$cam # mats[['cam']]
mats$ped # mats[['ped']]
ALTERNATIVELY
If you really want to get crazy you can take advantage of the get()
and assign()
functions. get()
calls an object by character, and assign()
can create one.
mats <- c('cam','ped')
mats.new <- NULL # initialize a matrix placeholder
for (i in 1:length(mats)) {
mats.new <- get(mats[i]) # save as a new matrix each loop
# use dimnames with a list input to do both the row and column at once
dimnames(mats.new) <- list(LETTERS[1:dim(mats.new)[1]],
LETTERS[1:dim(mats.new)[2]])
assign(mats[i],mats.new) # create (re-write) the matrix
}
Upvotes: 2
Reputation: 887128
If the datasets are placed in a list
we can use lapply
lst <- lapply(mget(mats), function(x) {
dimnames(x) <- list(LETTERS[seq_len(nrow(x))], LETTERS[seq_len(ncol(x))])
x})
It is better to keep it in a list
. In case the original objects needs to be changed
list2env(lst, envir = .GlobalEnv)
Upvotes: 1