CODEWITHSUNDEEP
javascript
J. Orange
J. Orange

Reputation: 11

How do I set up this API get request?

I am trying to get an API working which gets trivia questions from this site: https://opentdb.com/api_config.php. Here is my code:

if (auth && data.user == user && match('trivia', data.msg)) {
  $("button").click(function() {
    $.get("https://opentdb.com/api.php?amount=10&token=d6685dc31db69e33eeb1c3828ffa2c587d5ec43dc6dd995ebefe85681796d149", function(data, status) {
      sock.chat("Data: " + data + "\nStatus: " + status);
    });
  });
}

It doesn't 'sock.chat' anything, I am new to this so sorry if there is an obvious mistake. I am using this script on Tampermonkey on a website if that helps.

Upvotes: 0

Views: 983

Answers (3)

mahmood kabi
mahmood kabi

Reputation: 311

you can see detail of api response on below code. 

$.get("https://opentdb.com/api.php?amount=10&token=d6685dc31db69e33eeb1c3828ffa2c587d5ec43dc6dd995ebefe85681796d149", function(data, status) { 
 for(i = 0 ; i <data.results.length; i++){
     alert("category: " + data.results[i].category + "\n " +
           "correct_answer: " + data.results[i].correct_answer +  "\n "  +
           "difficulty: "+ data.results[i].difficulty +  "\n "  +
           "incorrect_answers: " + data.results[i].incorrect_answers.length +  "\n "  +
           "question: " + data.results[i].question +  "\n "  +
           "type: " + data.results[i].type +  "\n\n\n "  +
           "status: " + status);
 }

});

you can manipulate response with dom element instead of "alert" function.

Upvotes: 0

Dinesh undefined
Dinesh undefined

Reputation: 5546

This code is working. 

$.get("https://opentdb.com/api.php?amount=10&token=d6685dc31db69e33eeb1c3828ffa2c587d5ec43dc6dd995ebefe85681796d149", function(data, status) {
     console.log(data);
    });
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Upvotes: 1

thedude
thedude

Reputation: 9812

Here is a working example:

const url = "https://opentdb.com/api.php?amount=10&token=d6685dc31db69e33eeb1c3828ffa2c587d5ec43dc6dd995ebefe85681796d149";


fetch(url)
  .then(res => res.json())
  .then(json => console.log(json.results))
  .catch(error => console.error(error))

Upvotes: 2

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