CODEWITHSUNDEEP
pythonnlppyenchant
user7532121
user7532121

Reputation:

How to check to see if a string is contained in any english word?

Going off of this link: How to check if a word is an English word with Python?

Is there any way to see (in python) if a string of letters is contained in any word in the English language? For example, fun(wat) would return true since "water" is a word (and I'm sure there are multiple other words that contain wat) but fun(wayterlx) would be false since wayterlx is not contained in any English word. (and it is not a word itself)

Edit: A second example: d.check("blackjack") returns true but d.check("lackjac") returns false, but in the function I am looking for it would return true since it is contained in some english word.

Upvotes: 0

Views: 1977

Answers (1)

Azat Ibrakov
Azat Ibrakov

Reputation: 11009

Based on solution to the linked answer.

We can define next utility function using Dict.suggest method 

def is_part_of_existing_word(string, words_dictionary):
    suggestions = words_dictionary.suggest(string)
    return any(string in suggestion
               for suggestion in suggestions)

then simply

>>> import enchant
>>> english_dictionary = enchant.Dict("en")
>>> is_part_of_existing_word('wat', words_dictionary=english_dictionary)
True
>>> is_part_of_existing_word('wate', words_dictionary=english_dictionary)
True
>>> is_part_of_existing_word('way', words_dictionary=english_dictionary)
True
>>> is_part_of_existing_word('wayt', words_dictionary=english_dictionary)
False
>>> is_part_of_existing_word('wayter', words_dictionary=english_dictionary)
False
>>> is_part_of_existing_word('wayterlx', words_dictionary=english_dictionary)
False
>>> is_part_of_existing_word('lackjack', words_dictionary=english_dictionary)
True
>>> is_part_of_existing_word('ucumber', words_dictionary=english_dictionary)
True

Upvotes: 2

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