CODEWITHSUNDEEP
javaregexstring
Om Prakash
Om Prakash

Reputation: 2881

Regex starts with Capital letter and having length < 70

I want to match a string starting with capital letter and have length < 70.

I tried this regex ([A-Z][a-zA-Z\s\/\-]*\:?\'?) to check if the string starts with capital letter. It is working fine. But to check length, I changed to (([A-Z][a-zA-Z\s\/\-]*\:?\'?){4,70}) and it is not working.

Though, I can check the length using length() method of string in if statement. Doing so would make if statement lengthy. I want to combine length checking in regex itself. I think it can be done in regex, but I am not sure how.

Update(Forgot to mention): String can have either of two symbol- :,' and only one of two will be there for either zero or one time in the string.

E.g : Acceptable String : Looking forwards to an opportunity, WORK EXPERIENCE: , WORK EXPERIENCE- , India's Prime Minister

UnAcceptable String : Work Experience:: , Manager's Educational Qualification- , work experience: , Education - 2014 - 2017 , Education (Graduation)

Kindly help me.

Thanks in advance.

Upvotes: 1

Views: 2290

Answers (5)

Dhananjay Pareta
Dhananjay Pareta

Reputation: 1

Working REGEX = 

/\A^[A-Z][A-Za-z]*\z/

Upvotes: -1

Jan
Jan

Reputation: 43169

You'll certainly need anchors and lookarounds

(?=^[^-':\n]*[-':]{0,1}[^-':\n]*$)^[A-Z][-':\w ]{4,70}$

Thus, a string between 5-71 characters will be matched, see a demo on regex101.com. Additionally, it checks for the presence of zero or one of your Special characters (with the help of lookarounds, that is).

Upvotes: 3

davidxxx
davidxxx

Reputation: 131456

Specify a lookaround assertion at the start of the regex that asserts that it may contain between 4 and 70 characters :

(?=.{4,70}$)

You would write so :

String regex = "(?=.{4,70}$)[A-Z][a-zA-Z\\s\\/\\-]*\\:?\\'?";

Upvotes: 1

beny23
beny23

Reputation: 35038

I would add ^ and $ to your regex:

^[A-Z].{,69}$

should work. This means:

  • ^ beginning of the string
  • [A-Z] any capital character (in English anyway)
  • .{0,69} up to 69 other characters
  • $ end of the string

for a total length of up to 70 characters...

Upvotes: 3

Scary Wombat
Scary Wombat

Reputation: 44854

why would the if statement be lengthy?

    String str = "Scary";

    if (str.length() < 70 && str.charAt(0) >= 'A') {

    }

Upvotes: 1

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