CODEWITHSUNDEEP
javascript
Tyler L
Tyler L

Reputation: 845

Switch case for the index of an array

var testVar = [null, true, true, false, false];

//Paulpro's solution (not mine)
switch (testVar.indexOf( true )) {
  case 1:
    console.log('Im in the first group!');
    break;
  case 2:
    console.log('Im in the second group!');
    break;
  case 3:
    console.log('Im in the third group!');
    break;
}

testVar is an array like this [null, true, true, false, false, false] for an employee in the first group (index 1 is true) AND second group, but not the third group.

Upvotes: 3

Views: 5344

Answers (1)

Paul
Paul

Reputation: 141877

Find the position of true in the groups array (using indexOf) and use that for your switch statement:

contacts.forEach(function(employee, index){
  switch (employee.groups.indexOf( true )) {
    case 1:
      console.log('Im in the first group!');
      break;
    case 2:
      console.log('Im in the second group!');
      break;
  }
});

If the user can be in multiple groups it's better to use a series of if statements:

contacts.forEach(function(employee, index){
  if ( employee.groups[1] ) {
      console.log('Im in the first group!');
  }

  if ( employee.groups[2] ) {
      console.log('Im in the second group!');
  }
});

Upvotes: 3

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