Reputation: 1921
I have two lists:
alist = ['key1','key2','key3','key3','key4','key4','key5']
blist= [30001,30002,30003,30003,30004,30004,30005]
I want to merge these lists and add them to a dictionary.
I try dict(zip(alist,blist))
but this gives:
{'key3': 30003, 'key2': 30002, 'key1': 30001, 'key5': 30005, 'key4': 30004}
The desired form of the dictionary is:
{'key1': 30001, 'key2': 30002, 'key3': 30003,'key3':30003, 'key4': 30004, 'key4': 30004, 'key5': 30005}
I want to keep the duplicates in the dictionary as well as not join the values in the same key (... key3': 30003,'key3':30003,... ).Is it possible?
Thanks in advance.
Upvotes: 3
Views: 8469
Reputation: 2150
Great answer by @MoinuddinQuadri. I expanded it further to get the index as well:
my_dict = defaultdict(list)
for idx, tup in enumerate(zip(alist, blist)):
my_dict[tup[0]].append((idx, tup[1])
Upvotes: 0
Reputation: 48067
You can not do this as dict
objects can only have unique keys. Instead, you should use the list of tuple:
>>> alist = ['key1','key2','key3','key3','key4','key4','key5']
>>> blist= [30001,30002,30003,30003,30004,30004,30005]
>>> zip(alist, blist)
[('key1', 30001), ('key2', 30002), ('key3', 30003), ('key3', 30003), ('key4', 30004), ('key4', 30004), ('key5', 30005)]
If you want to access all the values based on the key, you may use collections.defaultdict
as:
>>> from collections import defaultdict
>>> my_dict = defaultdict(list)
>>> for k, v in zip(alist, blist):
... my_dict[k].append(v)
...
>>> my_dict
defaultdict(<type 'list'>, {'key3': [30003, 30003], 'key2': [30002], 'key1': [30001], 'key5': [30005], 'key4': [30004, 30004]})
You can access defaultdict
similar to normal dict objects. For example:
>>> my_dict['key3']
[30003, 30003]
Upvotes: 8
Reputation: 27869
As dict must use unique keys only, and if you insert same key twice the last one will be stored - this might be something you can use:
from itertools import groupby
alist = ['key1','key2','key3','key3','key4','key4','key5']
alist = [i for i, j in groupby(alist)]
blist = [30001,30002,30003,30003,30004,30004,30005]
blist = [list(j) for i, j in groupby(blist)]
print dict(zip(alist, blist))
#{'key3': [30003, 30003], 'key2': [30002], 'key1': [30001], 'key5': [30005], 'key4': [30004, 30004]}
If you want to preserve the key order as well you can use OrderedDict:
from collections import OrderedDict
print OrderedDict(zip(alist, blist))
Upvotes: 2
Reputation: 42678
A dictionary uses UNIQUE keys, so its imposible to have duplicates.
Upvotes: 3