CODEWITHSUNDEEP
phpjqueryjquery-plugins
jojio
jojio

Reputation: 19

jQuery star rating plugin

I am using this jQuery star rating plugin

But where do you add the link that points to the PHP file where the data is inserted in the database?

Upvotes: 0

Views: 2739

Answers (2)

jojio
jojio

Reputation: 19

This is what needs to be done:

$('input.wow').rating({
 callback: function(value){
            $.ajax({
        type: 'GET',
        url: "http://www3.inrees.com/rating_films_ajax.php?action=voter",
data:"films_id=<?php echo $id; ?>&rating="+value,
        success: function(){
         alert(value);
                 }
              })

  }
})

Question answered and my middle finger to the conceiver of the plugin

Upvotes: 1

Albireo
Albireo

Reputation: 11095

Check that page source code: it seems there is no file do specify: it's a simple HTML form:

<form name="api-select">
    <span class="star-rating-control">
        <div class="rating-cancel"><a title="Cancel Rating"></a></div>
        <div class="star-rating rater-0 star star-rating-applied star-rating-live star-rating-on"><a title="A">A</a></div>
        <div class="star-rating rater-0 star star-rating-applied star-rating-live star-rating-on"><a title="B">B</a></div>
        <div class="star-rating rater-0 star star-rating-applied star-rating-live star-rating-on"><a title="C">C</a></div>
        <div class="star-rating rater-0 star star-rating-applied star-rating-live"><a title="D">D</a></div>
        <div class="star-rating rater-0 star star-rating-applied star-rating-live"><a title="E">E</a></div>
    </span>
    <input style="display: none;" class="star star-rating-applied" name="api-select-test" value="A" type="radio">
    <input style="display: none;" class="star star-rating-applied" name="api-select-test" value="B" type="radio">
    <input style="display: none;" class="star star-rating-applied" name="api-select-test" value="C" type="radio">
    <input style="display: none;" class="star star-rating-applied" name="api-select-test" value="D" type="radio">
    <input style="display: none;" class="star star-rating-applied" name="api-select-test" value="E" type="radio">
    <input value="Submit »" onclick="$(this).next().html( $(this.form).serialize() || '(nothing submitted)' );" type="button">
</form>

Therefore I think you should just set your action and method attributes on the form element.

Upvotes: 0

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