CODEWITHSUNDEEP
swiftswifty-json
user7748962
user7748962

Reputation:

swiftyjson - Call can throw, but it is marked with 'try' and the error is not handled

I am trying to use swiftyjson and I am getting an Error:

Call can throw, but it is marked with 'try' and the error is not handled.

I have validated that my source JSON is good. I've been searching and cannot find a solution to this problem 

import Foundation


class lenderDetails
{

func loadLender()
{

    let lenders = ""

    let url = URL(string: lenders)!
    let session =  URLSession.shared.dataTask(with: url)
    {
        (data, response, error) in


        guard let data = data else
        {
            print ("data was nil?")
            return
        }

        let json = JSON(data: data)
        print(json)
    }

    session.resume()
}
}

Thank you for all the help!

Upvotes: 13

Views: 16051

Answers (3)

vadian
vadian

Reputation: 285082

The SwiftyJSON initializer throws, the declaration is 

public init(data: Data, options opt: JSONSerialization.ReadingOptions = []) throws

You have three options:

  1. Use a do - catch block and handle the error (the recommended one).

    do {
   let json = try JSON(data: data)
   print(json)
} catch {
   print(error)
   // or display a dialog
}

  2. Ignore the error and optional bind the result (useful if the error does not matter).

    if let json = try? JSON(data: data) {
   print(json)
}

  3. Force unwrap the result 

    let json = try! JSON(data: data)
print(json)

    Use this option only if it's guaranteed that the attempt will never fail (not in this case!). Try! can be used for example in FileManager if a directory is one of the default directories the framework creates anyway.

For more information please read Swift Language Guide - Error Handling

Upvotes: 59

Rashwan L
Rashwan L

Reputation: 38833

You should wrap it into a do-catch block. In your case:

do {
    let session =  URLSession.shared.dataTask(with: url) {
        (data, response, error) in
            guard let data = data else {
            print ("data was nil?")
            return
        }

        let json = JSON(data: data)
        print(json)
    }
} catch let error as NSError {
    // error
}

Upvotes: 4

noob
noob

Reputation: 555

Probably you need to implement do{} catch{} block. Inside do block you have to call throwable function with try.

Upvotes: 0

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