CODEWITHSUNDEEP
gitbashsvnsed
DenCowboy
DenCowboy

Reputation: 15086

Use sed to filter output from git log

I did some svn to git migration. Now I use git log to find the svn revision (which is described in the commit message of git).

$ git log -1 11.10.11.0

output

commit 84a1f5fb6xxx4607e6ed5623eab15ecdbacf
Author: USER <USER>
Date:   Wed Apr 12 08:27:08 2017 +0000

    git-svn-id: https://svn-repo.com/repo/proj/tags/11.10.11.0@12000 f25b8xx2b0-ax00-41x2-87xx1-abxxxxe8fa

Now I want to use sed to filter the revision number (12000) in this case. What's the most generic way to do this?

Upvotes: 0

Views: 833

Answers (2)

CWLiu
CWLiu

Reputation: 4043

The awk command can meet your requirement, take a look at below,

git log -1 11.10.11.0 | awk -F'@' '{printf "%s",$2}' | awk '{print $1}'
12000

Upvotes: 1

P....
P....

Reputation: 18381

sed approach: Here sed two actions are performed by sed. One is to only print the desired line and other is to print the desired section of line. 

<git-command>|sed -r '/git-svn-id/!d;s/.*@([^ ]+).*/\1/'
12000

If grep is acceptable approach to you: 

<git-command>|grep -oP 'git-svn-id.*?@\K[^ ]+'
12000

If awk is acceptable:

<git-command>|awk '/git-svn-id/{n=split($2,a,"@");print a[n]}'
12000

Upvotes: 3

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