Reputation: 85
For example,
dataX = data.frame(a=c(1:5),b=c(2:6),c=c(3:7),d=c(4:8),e=c(5:9),f=c(6:10))
How do I insert a blank column after every 2 columns?
Upvotes: 3
Views: 48
Reputation: 38500
Here is a similar method that uses a trick with matrices and integer selection of columns. The original data.frame gets an NA column with cbind
. The columns of this new object are then referenced with every two columns and then the final NA column using a matrix to fill in the final column with rbind
.
cbind(dataX, NewCol=NA)[c(rbind(matrix(seq_along(dataX), 2), ncol(dataX)+1))]
a b NewCol c d NewCol.1 e f NewCol.2
1 1 2 NA 3 4 NA 5 6 NA
2 2 3 NA 4 5 NA 6 7 NA
3 3 4 NA 5 6 NA 7 8 NA
4 4 5 NA 6 7 NA 8 9 NA
5 5 6 NA 7 8 NA 9 10 NA
Upvotes: 3
Reputation: 887148
We can use use split
to split the dataset at unique positions into a list
of data.frame
, loop through the list
, cbind
with NA
and cbind
the elements together
res <- do.call(cbind, setNames(lapply(split.default(dataX, (seq_len(ncol(dataX))-1)%/%2),
function(x) cbind(x, NewCol = NA)), NULL))
res
# a b NewCol c d NewCol e f NewCol
#1 1 2 NA 3 4 NA 5 6 NA
#2 2 3 NA 4 5 NA 6 7 NA
#3 3 4 NA 5 6 NA 7 8 NA
#4 4 5 NA 6 7 NA 8 9 NA
#5 5 6 NA 7 8 NA 9 10 NA
names(res) <- make.unique(names(res))
Upvotes: 2
Reputation: 1795
Let us construct a empty data frame with the same number of rows as dataX
empty_df <- data.frame(x1=rep(NA,nrow(df)),x2=rep(NA,nrow(df)),x3=rep(NA,nrow(df)))
dataX<-cbind(dataX,empty_df)
dataX<-dataX[c("a","b","x1","c","d","x2","e","f","x3")]
resulting in:
a b x1 c d x2 e f x3
1 1 2 NA 3 4 NA 5 6 NA
2 2 3 NA 4 5 NA 6 7 NA
3 3 4 NA 5 6 NA 7 8 NA
4 4 5 NA 6 7 NA 8 9 NA
5 5 6 NA 7 8 NA 9 10 NA
Upvotes: 0