Reputation: 6325
function getInputElements() {
var inputs = document.getElementsByTagName("input");
}
The above code gets all the input
elements on a page which has more than one form. How do I get the input
elements of a particular form using plain JavaScript?
Upvotes: 91
Views: 233975
Reputation: 57446
.elements
and Object.fromEntries(new FormData(form))
have been mentioned, but here's a runnable, complete example to supplement the existing answers:
document.querySelector("form").addEventListener("submit", event => {
event.preventDefault();
// work with individual entries:
const {elements} = event.target;
const username = elements["username"].value;
const password = elements["password"].value;
console.log({username, password});
// or extract all named input entries:
const data = Object.fromEntries(new FormData(event.target));
console.log(data);
});
<form>
<div>
<label for="username">Username:</label>
<input id="username" name="username" required />
</div>
<div>
<label for="password">Password:</label>
<input id="password" name="password" required />
</div>
<input type="submit" value="Login" />
</form>
The name=""
fields are the keys in the elements
object.
Upvotes: 0
Reputation: 1677
This answer generates a JavaScript Object containing all the form field names and values, in correct order. It combines several of the answers here.
It works by first finding the form element. Then it generates a NodeList of all the form's elements that have a NAME attribute. Then it paws through those elements, constructing the Object from the names and values of each element.
This technique is useful for submitting a form on the same page (using fetch
if you do want to use PHP), without using GET or POST to do a page request. The tab's history is not changed, and no redirection is needed.
Here is a full, working example:
<!DOCTYPE html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
</head>
<body>
<form id=main>
Enter name:
<input type=text name=fname value=MyName>
<select name=fselect rows=1>
<option selected>MyChoice</option>
</select><br>
<textarea name=ftextarea>MyTextarea</textarea>
<input type=button name=fbutton
value=SubmitButton onclick='Submit()'>
</form>
<script>
function Submit()
{
const main = document.getElementById('main');
const nodeList = main.querySelectorAll('[name]');
const fields = {};
Array.from(nodeList).forEach(node =>
{fields[node.name] = node.value;});
console.log(fields);
/* Shows: {fname: 'MyName', fselect: 'MyChoice',
ftextarea: 'MyTextarea', fbutton: 'SubmitButton'} */
} // Submit
</script>
</body>
</html>
Upvotes: 0
Reputation: 31841
If you have a reference to any field in the form or an event then you don't need to explicitly look up the form since every form field has a form
attribute that points to its parent form (if there is one, of course). That means that once you have a field reference to a DOM element userName
then userName.form
will be the form. If $userName
is a jQuery object, then $userName.get(0).form
will give you the form.
If you have an event then it will contain a target
attribute which will point to the form field that triggered the event, which means you can access the form via myEvent.target.form
.
Here is an example without any form lookup code.
function doLogin(e) {
e = e || window.event;
e.preventDefault();
// e.target is the submit button
var form = e.target.form;
if (form.login.value && form.password.value) {
alert("Submitting form — user:" + form.login.value + " password:" + form.password.value);
form.submit();
} else {
alert('Please fill in the form!');
}
}
<html>
<body>
<form name="frm">
<input type="text" name="login"><br />
<input type="password" name="password"><br />
<button type="submit" onclick="doLogin()">Login</button>
</form>
</body>
</html>
If you have multiple forms on the page you still don't need to label them by name or id, because you'll always get the correct form instance via the event or via a reference to a field.
Upvotes: 4
Reputation: 8710
Loosely relevant but if you'd like to get all of the form items in an object you can:
Object.fromEntries(new FormData(document.querySelector('form')).entries())
Which yields
{
email: "[email protected]",
password: "mypassword"
}
Upvotes: 8
Reputation: 598
const contactForm = new FormData("formLocatorIdIsAdviceableAsTheLocator");
The above is handy regardless of context(framework or pure js because):
For more: https://developer.mozilla.org/en-US/docs/Web/API/FormData/FormData
Upvotes: 0
Reputation: 2115
It is also possible to use this:
var user_name = document.forms[0].elements[0];
var user_email = document.forms[0].elements[1];
var user_message = document.forms[0].elements[2];
All the elements of forms are stored in an array by Javascript. This takes the elements from the first form and stores each value into a unique variable.
Upvotes: 11
Reputation: 41
You can select by simply taking all elements that contain the attribute name
let form = document.querySelector("form");
form.querySelectorAll("[name]");
This will return all relevant elements of the form.
Upvotes: 3
Reputation: 491
You can use FormData if you want the values:
var form = document.getElementById('form-name');
var data = new FormData(form);
for (var [key, value] of data) {
console.log(key, value)
}
Upvotes: 27
Reputation: 1606
I could have sworn there used to be a convenient fields
property on a form but … Must have been my imagination.
I just do this (for <form name="my_form"></form>
) because I usually don't want fieldsets themselves:
let fields = Array.from(document.forms.my_form.querySelectorAll('input, select, textarea'));
Upvotes: 0
Reputation: 1313
let formFields = form.querySelectorAll(`input:not([type='hidden']), select`)
ES6 version that has the advantage of ignoring the hidden fields if that is what you want
Upvotes: 1
Reputation: 207557
var inputs = document.getElementById("formId").getElementsByTagName("input");
var inputs = document.forms[1].getElementsByTagName("input");
Update for 2020:
var inputs = document.querySelectorAll("#formId input");
Upvotes: 9
Reputation: 575
const getAllFormElements = element => Array.from(element.elements).filter(tag => ["select", "textarea", "input"].includes(tag.tagName.toLowerCase()));
const pageFormElements = getAllFormElements(document.body);
console.log(pageFormElements);
const pageFormElements = getAllFormElements(document.getElementById("my-form"));
console.log(formElements);
Upvotes: 12
Reputation: 516
Try this to get all the form fields.
var fields = document['formName'].elements;
Upvotes: 5
Reputation: 324737
document.getElementById("someFormId").elements;
This collection will also contain <select>
, <textarea>
and <button>
elements (among others), but you probably want that.
Upvotes: 177
Reputation: 20007
If you only want form elements that have a name
attribute, you can filter the form elements.
const form = document.querySelector("your-form")
Array.from(form.elements).filter(e => e.getAttribute("name"))
Upvotes: 2
Reputation: 866
Use this
var theForm = document.forms['formname']
[].slice.call(theForm).forEach(function (el, i) {
console.log(el.value);
});
The el stands for the particular form element. It is better to use this than the foreach loop, as the foreach loop also returns a function as one of the element. However this only returns the DOM elements of the form.
Upvotes: 5
Reputation: 627
SIMPLE Form code
<form id="myForm" name="myForm">
<input type="text" name="User" value="Arsalan"/>
<input type="password" name="pass" value="123"/>
<input type="number" name="age" value="24"/>
<input type="text" name="email" value="[email protected]"/>
<textarea name="message">Enter Your Message Her</textarea>
</form>
Javascript Code
//Assign Form by Id to a Variabe
var myForm = document.getElementById("myForm");
//Extract Each Element Value
for (var i = 0; i < myForm.elements.length; i++) {
console.log(myForm.elements[i].value);
}
JSFIDDLE : http://jsfiddle.net/rng0hpss/
Upvotes: 7
Reputation: 351
You're all concentrating on the word 'get' in the question. Try the 'elements' property of any form which is a collection that you can iterate through i.e. you write your own 'get' function.
Example:
function getFormElelemets(formName){
var elements = document.forms[formName].elements;
for (i=0; i<elements.length; i++){
some code...
}
}
Hope that helps.
Upvotes: 25
Reputation: 360066
How would you like to differentiate between forms? You can use different IDs, and then use this function:
function getInputElements(formId) {
var form = document.getElementById(formId);
if (form === null) {
return null;
}
return form.getElementsByTagName('input');
}
Upvotes: 1