CODEWITHSUNDEEP
bashmacos
AAlred
AAlred

Reputation: 85

Bash script error: line 167: syntax error near unexpected token 'then'

I am getting an error in my bash script and I don't see anything wrong with it. Here is the code that is giving me the error.

if [ "$password" = "na" ]; then  
   log "Password not set"  
   usage  
   exit 1  
fi

Could anyone see anything wrong with this? It looks fine to me but I am also pretty new to bash in general.

EDIT: Here are the previous lines of code, maybe that will help.

if [ "$SITE" = "unknown" ]; then
    log "Site not set"
    usage
    exit 1
fi

if [ "$VERSION" = "na" ]; then
    log "Version not set"
    usage
    exit 1
fi

if [ "$password" = "na" ]; then  
   log "Password not set"  
   usage  
   exit 1  
fi

Upvotes: 1

Views: 1260

Answers (1)

Dale_Reagan
Dale_Reagan

Reputation: 2061

Your example works without errors for me. I will guess that your file may contain 'hidden' characters (most likely a '\r' - carriage return - but could be something else). Use to native Vi/Vim family of editors to avoid this; otherwise, check the settings in your text editor and set your 'line endings' to Unix/OSX. Try this:

tr -d '\r' /path/your_file.sh > /path/your_file.mod.sh  

bash -n /path/your_file.sh      ## should show error
bash -n /path/your_file.mod.sh  ## no errors

:)
Dale

Upvotes: 2

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