CODEWITHSUNDEEP
pythonpython-3.xkivykivy-language
blakebullwinkel
blakebullwinkel

Reputation: 335

Kivy: How to check for the existence of a child widget

In my .py file I have a screen that looks something like:

class ExampleScreen(Screen):
    def create_layout(self):
        box = BoxLayout(orientation='vertical')
        # other layout stuff in here
        self.add_widget(box)

In my .kv file, I have a button which, when pressed, calls this function and displays this layout on <ExampleScreen>. However, I would like to be able to press this button and first check if this layout already exists, and if so, remove it before adding a new one. I anticipate modifying create_layout() to something like:

def create_layout(self):
    if (box layout child has already been added):
        self.remove_widget(box layout child)
    box = BoxLayout(orientation='vertical')
    # other layout stuff in here
    self.add_widget(box)

Does anyone know how to do this? Using id somehow?

Upvotes: 6

Views: 5060

Answers (2)

Yoav Glazner
Yoav Glazner

Reputation: 8066

Each widget has a children property so you may want to use it.

for c in list(self.children):
    if isinstance(c, BoxLayout): self.remove(c)

You can also assign it to the widget: (as mentioned in Edvardas Dlugauskas anwser)

def __init__(self, **kw):
    self.box = None
    ...


def create_layout(self):
    if self.box: self.remove(self.box) 
    self.box = BoxLayout(orientation='vertical')
    self.add_widget(box)

Upvotes: 5

Edvardas Dlugauskas
Edvardas Dlugauskas

Reputation: 1489

Well, you can do it with an id or some other child checks, but the easiest and most straight-forward way would be to have a boolean flag in your class that would change to True when you added the widget and False when you removed it. Otherwise, you can also create a kivy box_obj = ObjectProperty(None) and do self.box_obj = box and then check if the self.box_obj is not None.

Upvotes: -1

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