Reputation: 229
<html>
<table border="1">
<tbody>
<tr>
<td>
<table border="1">
<tbody>
<tr>
<th>aaa</th>
<th>bbb</th>
<th>ccc</th>
<th>ddd</th>
<th>eee</th>
<th>fff</th>
</tr>
<tr>
<td>111</td>
<td>222</td>
<td>333</td>
<td>444</td>
<td>555</td>
<td>666</td>
</tr>
</tbody>
</table>
</td>
</tr>
</tbody>
</table>
</html>
How can i select specific related cousin data using xpath, The desired output would be be:
<th>aaa</th>
<th>ccc</th>
<th>fff</th>
<td>111</td>
<td>333</th>
<td>666</td>
The most important aspect of the xpath is that i am looking to be able to include or exclude certain <th>
tags and their corresponding <td>
tags
So based on the answers so far the closest I have is:
//th[not(contains(text(), "ddd"))] | //tr[2]/td[not(position()=4)]
Is there any way of not explicitly using position()=4
but instead reference the corresponding th
tag
Upvotes: 1
Views: 324
Reputation: 52685
I'm not sure that this is the best solution, but you might try
//th[not(.="bbb") and not(.="ddd") and not(.="eee")] | //tr[2]/td[not(position()=index-of(//th, "bbb")) and not(position()=index-of(//th, "ddd")) and not(position()=index-of(//th, "eee"))]
or shorter version
//th[not(.=("bbb", "ddd", "eee"))]| //tr[2]/td[not(position()=(index-of(//th, "bbb"), index-of(//th, "ddd"),index-of(//th, "eee")))]
<th>aaa</th>
<th>ccc</th>
<th>fff</th>
<td>111</td>
<td>333</td>
<td>666</td>
You can avoid using complicated XPath
expressions to get required output. Try to use Python
+ Selenium
features instead:
# Get list of th elements
th_elements = driver.find_elements_by_xpath('//th')
# Get list of td elements
td_elements = driver.find_elements_by_xpath('//tr[2]/td')
# Get indexes of required th elements - [0, 2, 5]
ok_index = [th_elements.index(i) for i in th_elements if i.text not in ('bbb', 'ddd', 'eee')]
for i in ok_index:
print(th_elements[i].text)
for i in ok_index:
print(td_elements[i].text)
Output is
'aaa'
'ccc'
'fff'
'111'
'333'
'666'
If you need XPath 1.0
solution:
//th[not(.=("bbb", "ddd", "eee"))]| //tr[2]/td[not(position()=(count(//th[.="bbb"]/preceding-sibling::th)+1, count(//th[.="ddd"]/preceding-sibling::th)+1, count(//th[.="eee"]/preceding-sibling::th)+1))]
Upvotes: 0
Reputation: 167716
Using XPath 3.0 you can structure that into
let $th := //table/tbody/tr[1]/th,
$filteredTh := $th[not(. = ("bbb", "ddd", "eee"))],
$pos := $filteredTh!index-of($th, .)
return ($filteredTh, //table/tbody/tr[position() gt 1]/td[position() = $pos])
Upvotes: 1