Reputation: 1301
having a problem with browser form validation using .preventDefault()
Is there a way to let browser check validation of required inputs, but stops submit?
Is there any flags I can use to get if form is valid?
Thanks
update: using both backbone and jquery
events: {
"click #commentFormSubmit": "commentFormSubmit",
},
commentFormSubmit: function(el){
el.preventDefault();
var $el = $(el.target).parent();
// this.$el.find('button').prop('disabled', true).addClass('disabled');
var commentData = {};
commentData.name = this.$el.find('input[name=comment_name]').val();
commentData.country = this.$el.find('input[name=comment_country]').val();
commentData.email = this.$el.find('input[name=comment_email]').val();
commentData.comment = this.$el.find('textarea[name=comment_text]').val();
commentData.grade = this.$el.find('.commnt_grade:checked').val();
console.log('dd')
this.model.onSubmitComment(commentData);
},
and the form:
<form action="" class="" method="post">
<span>
<input type="text" name="comment_name" class="comment_input" placeholder="{{ 'your name'|_ }}" required>
<input type="text" name="comment_country" class="comment_input" placeholder="{{ 'country'|_ }}">
<input type="text" name="comment_email" class="comment_input" placeholder="{{ 'your email'|_ }}" required>
</span>
<textarea name="comment_text" id="comment_text" cols="30" rows="10" placeholder="{{ 'your comment'|_ }}" required></textarea>
<span class="grades">
<input type="radio" name="commnt_grade" class="commnt_grade" id="grade_1" value="1">
<label for="grade_1" class="selectGrades" data-eq="1"></label>
<input type="radio" name="commnt_grade" class="commnt_grade" id="grade_2" value="2">
<label for="grade_2" class="selectGrades" data-eq="2"></label>
<input type="radio" name="commnt_grade" class="commnt_grade" id="grade_3" value="3">
<label for="grade_3" class="selectGrades" data-eq="3"></label>
<input type="radio" name="commnt_grade" class="commnt_grade" id="grade_4" value="4">
<label for="grade_4" class="selectGrades" data-eq="4"></label>
<input type="radio" name="commnt_grade" class="commnt_grade" id="grade_5" value="5">
<label for="grade_5" class="selectGrades" data-eq="5"></label>
</span>
<button type="submit" id="commentFormSubmit">{{ 'submit'|_ }}</button>
</form>
Upvotes: 16
Views: 12576
Reputation: 2609
While @TJ provided a good solution in his answer, the alternative method is to listen for the submit
event on the actual form while using event.preventDefault()
. This will allow the form validation to trigger but prevent the form submit.
Upvotes: 7
Reputation: 1301
Thanks for @T.J. Crowder for the direction. as for me it's a fix, not a solution.
commentFormSubmit: function(el){
var $el = $(el.target).parent();
if ($el[0].checkValidity()){
el.preventDefault();
// this.$el.find('button').prop('disabled', true).addClass('disabled');
var commentData = {};
commentData.name = this.$el.find('input[name=comment_name]').val();
commentData.country = this.$el.find('input[name=comment_country]').val();
commentData.email = this.$el.find('input[name=comment_email]').val();
commentData.comment = this.$el.find('textarea[name=comment_text]').val();
commentData.grade = this.$el.find('.commnt_grade:checked').val();
// this.model.onSubmitComment(commentData);
}
else $el[0].reportValidity();
},
Again, thanks!
Upvotes: 0
Reputation: 1074355
If you want to validate without submitting, you can get the browser to check the validity of the form by calling checkValidity
on it, and to report the validity by calling reportValidity
. (On browsers that support HTML validation.)
Calling both checks and then reports, without submitting:
yourFormElement.checkValidity();
yourFormElement.reportValidity();
Example:
$("input[type=button]").on("click", function() {
var yourFormElement = $("form")[0];
yourFormElement.checkValidity();
yourFormElement.reportValidity();
});
<form>
<input type="text" required>
<br><input type="text" required>
<br><input type="button" value="Click to check">
</form>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
You can also do it at the individual element level:
yourInputElement.checkValidity();
yourInputElement.reportValidity();
Example:
$("input[type=button]").on("click", function() {
var yourInputElement = $("#second")[0];
yourInputElement.checkValidity();
yourInputElement.reportValidity();
});
<form>
<input id="first" type="text" required>
<br><input id="second" type="text" required>
<br><input type="button" value="Click to check second field only">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
Since you've mentioned you're using jQuery, I'll just emphasize that these are methods of the DOM element, not the jQuery object. So for instance, if your form has an id
and you look it up like this:
var $myForm = $("#the-form");
then you'd use
$myForm[0].checkValidity();
$myForm[0].reportValidity();
not
$myForm.checkValidity(); // Wrong
$myForm.reportValidity(); // Wrong
Or you could give yourself a little plugin for it:
jQuery.fn.checkValidity = function() {
var el = this[0];
return el && el.checkValidity();
};
jQuery.fn.reportValidity = function() {
var el = this[0];
return el && el.reportValidity();
};
That's in keeping with jQuery's various other "getters" in that it only looks at the first element in the set inside the jQuery object.
Upvotes: 19
Reputation: 5711
You can always rely to HTML5 form validation attributes that prevents you to submit your request while you have invalid form data:
So you do not need to prevent default behavior - use can't submit form until you have invalid data.
<form action="/action_page_post.php" method="post">
<input type="text" name="fname" required>
<input type="submit" value="Submit">
</form>
https://www.w3schools.com/js/js_validation.asp
Upvotes: -3