Reputation: 867
i need a way to initialize const elements of an array for the program i am currently working on. The problem is that i have to initialize these elements with a function, there is no way to do it like this:
const int array[255] = {1, 1278632, 188, ...};
because its alot of data i have to generate. What i tried is to memcpy data to the const int's but that can't work and hasn't worked.
const int array[255];
void generateData(){
for(int i = 0; i < 255; i++) {
initializeSomehowTo(5, array[i]);
}
}
I hope you understand what i am trying, sorry if i doubled the question, i must have overlooked it.
Upvotes: 17
Views: 7253
Reputation: 20403
How about this?
#include <array>
typedef std::array<int, 255> Array;
const Array array = generateData();
Array generateData(){
Array a;
for(int i = 0; i < a.size(); i++) {
initializeSomehowTo(a[i]);
}
return a;
}
Upvotes: 20
Reputation: 10685
You can create a writable array, initialize it, and, then, create a const reference to it.
int arry[255];
void generateData(){
for(int i = 0; i < 255; i++) {
initializeSomehowTo(5, arry[i]);
}
}
const int (&array)[255] = arry;
Upvotes: 3
Reputation: 154045
The easiest approach is to get the filled array from a function and use that to initialize your const
(or constexpr
) object. However, built-in arrays can't be copied but std::array<T, N>
be:
std::array<T, 255> array = initializeData();
If you need a built-in array, I can imagine initializing a static
member of a class (template, actually) where the index is expanded from indices expanded from an std::make_index_sequence<255>
and used as positional argument in the array, i.e., something along these lines:
#include <algorithm>
#include <iostream>
#include <iterator>
#include <utility>
int some_function(std::size_t i) { return i; }
template <typename> struct initialized_array_base;
template <std::size_t... I>
struct initialized_array_base<std::index_sequence<I...>> {
static const int array[sizeof...(I)];
};
template <std::size_t... I>
int const initialized_array_base<std::index_sequence<I...>>::array[sizeof...(I)]
= { some_function(I)... };
struct initialized_array
:initialized_array_base<std::make_index_sequence<256>> {
};
int main() {
std::copy(std::begin(initialized_array::array),
std::end(initialized_array::array),
std::ostream_iterator<int>(std::cout, " "));
std::cout << '\n';
}
Upvotes: 6