CODEWITHSUNDEEP
python
hpotter054
hpotter054

Reputation: 29

how to convert a list into a list of tuples?

Here's what I have in the text file:

1712 Albert
1703 Benny
1799 Henry
1735 Jessica
1722 Lucas
1701 Luke
1757 William
1777 Jenny
1783 Lucia
1764 Venus
1718 Felicitas

Here's what I have done to read the file but I have no idea how to put them into a list of tuples

def readRecords(filepath):
    file = open('Students1.txt', 'r')
    filecontent = file.readlines()
    file.close()
    return filecontent

Here's what the output is supposed to be:

Output file

Upvotes: 0

Views: 1152

Answers (7)

Luis Miguel Mendes
Luis Miguel Mendes

Reputation: 1

Location = ["1712","1703","1799",...]
Name = ["Albert","Benny","Henry",...]

using a zip function:

z = zip(Location, Name)
print z

Output:

[("1712","Albert"),("1703","Benny"),...]

Upvotes: -2

syntaxError
syntaxError

Reputation: 866

If you want a nice short two line method:

lines = [x.rstrip() for x in open('students.txt')]
output = [tuple(pair.split(' ')) for pair in lines]

print(output)
# [('1712', 'Albert'), ('1703', 'Benny'), ('1799', 'Henry')...

Upvotes: 0

falsetru
falsetru

Reputation: 369454

def readRecords(filepath):
    result = []
    with open('Students1.txt', 'r') as f:  # close the file outside of `with`
        for line in f:  # Iterate over lines
            num, name = line.split()  # split line into two part
            num = int(num)  # convert number part to `int`
            result.append((num, name))
    return result

NOTE: Don't use readlines() unless you need whole lines at once. You just need a line at a time; iterating a file is enough.

Upvotes: 1

Jon Kiparsky
Jon Kiparsky

Reputation: 7773

Given the lines as you're reading them from the file, the following will work:

def process_lines(lines):
    result = []
    for line in lines:
        parts = line.strip().split(" ")
        result.append(tuple(int(parts[0]), parts[1]))
    return result

A list comprehension is possible here, but it requires a lot of straining. Use listcomps when they simplify your code, avoid them when they make it more complicated. (or when they require you to calculate the same value twice)

Upvotes: 0

Daniel
Daniel

Reputation: 2295

def readRecords(filepath):
   rst = []
   with open(filepath) as f:
        data = f.read().splitlines()
        rst = [(int(x.split(' ')[0]), x.split(' ')[1]) for x in data]
   return rst

Upvotes: 1

McGrady
McGrady

Reputation: 11487

Just open the file, and then split these lines, I realized that the result you need is like (int, string) ,so you can use map to do this and then return tuple:

with open('out.csv') as f:
    print([tuple(map(lambda x: int (x) if x.isdigit() else x,i.split())) for i in f])

Output:

[(1712, 'Albert'), (1703, 'Benny'), (1799, 'Henry'), (1735, 'Jessica'), (1722, 'Lucas'), (1701, 'Luke'), (1757, 'William'), (1777, 'Jenny'), (1783, 'Lucia'), (1764, 'Venus'), (1718, 'Felicitas')]

Upvotes: 1

Pedro von Hertwig Batista
Pedro von Hertwig Batista

Reputation: 3012

You must iterate over the lines in the file you just read. Here's what you could do:

def readRecords(filepath):
    file = open(filepath, 'r')  # You should use the filepath variable you've given
    filecontent = file.readlines()
    file.close()

    my_tuples = []
    for line in filecontent:  # For each line in the file...
        line = line.strip()  # Remove the newline character which you likely don't want
        my_tuples.append(int((line.split(' ')[0]), line.split(' ')[1]))  # Create a tuple of the two words separated by a space

    return my_tuples

print(readRecords('Students1.txt'))

Upvotes: 0

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