CODEWITHSUNDEEP
pythondictionary
yariv bar
yariv bar

Reputation: 976

Find key different from given key when iterating list of dictionaries

I have list of dictionaries and in each one of them the key site exists. So in other words, this code returns True:

all('site' in site for site in summary)

Question is, what will be the pythonic way to iterate over the list of dictionaries and return True if a key different from site exists in any of the dictionaries?

Example: in the following list I would like to return True because of the existence of cost in the last dictionary BUT, I can't tell what will be the other key, it can be cost as in the example and it can be other strings; random keys for that matter.

[
    {"site": "site_A"},
    {"site": "site_B"},
    {"site": "site_C", "cost": 1000}
]

Upvotes: 1

Views: 46

Answers (3)

zipa
zipa

Reputation: 27879

This is a bit longer version, but it gives you what you need. Just to give more options:

any({k: v for k, v in site.items() if k != 'site'} for site in summary)

Upvotes: 0

acdr
acdr

Reputation: 4716

You could just check, for each dictionary dct:

any(key != "site" for key in dct)

If you want to check this for a list of dictionaries dcts, shove another any around that: any(any(key != "site" for key in dct) for dct in dcts)

This also makes it easily extensible to allowing multiple different keys. (E.g. any(key not in ("site", "otherkey") for key in dct)) Because what's a dictionary good for if you can only use one key?

Upvotes: 2

Martijn Pieters
Martijn Pieters

Reputation: 1122262

If all dictionaries have the key site, the dictionaries have a length of at least 1. The presence of any other key would increase the dictionary size to be greater than 1, test for that:

any(len(d) > 1 for d in summary)

Upvotes: 7

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