Strict aliasing rule and strlen implementation of glibc

Question

I have been reading about the strict aliasing rule for a while, and I'm starting to get really confused. First of all, I have read these questions and some answers:

• strict-aliasing-rule-and-char-pointers
• when-is-char-safe-for-strict-pointer-aliasing
• is-the-strict-aliasing-rule-really-a-two-way-street

According to them (as far as I understand), accessing a char buffer using a pointer to another type violates the strict aliasing rule. However, the glibc implementation of strlen() has such code (with comments and the 64-bit implementation removed):

size_t strlen(const char *str)
{
    const char *char_ptr;
    const unsigned long int *longword_ptr;
    unsigned long int longword, magic_bits, himagic, lomagic;

    for (char_ptr = str; ((unsigned long int) char_ptr 
             & (sizeof (longword) - 1)) != 0; ++char_ptr)
       if (*char_ptr == '\0')
           return char_ptr - str;

    longword_ptr = (unsigned long int *) char_ptr;

    himagic = 0x80808080L;
    lomagic = 0x01010101L;

    for (;;)
    { 
        longword = *longword_ptr++;

        if (((longword - lomagic) & himagic) != 0)
        {
            const char *cp = (const char *) (longword_ptr - 1);

            if (cp[0] == 0)
                return cp - str;
            if (cp[1] == 0)
                return cp - str + 1;
            if (cp[2] == 0)
                return cp - str + 2;
            if (cp[3] == 0)
                return cp - str + 3;
        }
    }
}

The longword_ptr = (unsigned long int *) char_ptr; line obviously aliases an unsigned long int to char. I fail to understand what makes this possible. I see that the code takes care of alignment problems, so no issues there, but I think this is not related with the strict aliasing rule.

The accepted answer for the third linked question says:

However, there is a very common compiler extension allowing you to cast properly aligned pointers from char to other types and access them, however this is non-standard.

Only thing comes to my mind is the -fno-strict-aliasing option, is this the case? I could not find it documented anywhere what glibc implementors depend on, and the comments somehow imply that this cast is done without any concerns like it is obvious that there will be no problems. That makes me think that it is indeed obvious and I am missing something silly, but my search failed me.

Answer 1

When writing the aliasing rules, the authors of the Standard only considered forms that would be useful, and should thus be mandated, on all implementations. C implementations are targeted toward a variety of purposes, and the authors of the Standard make no attempt to specify what a compiler must do to be suitable for any particular purpose (e.g. low-level programming) or, for that matter, any purpose whatsoever.

Code like the above which relies upon low-level constructs should not be expected to run on compilers that make no claim of being suitable for low-level programming. On the flip side, any compiler which can't support such code should be viewed as unsuitable for low-level programming. Note that compilers can employ type-based aliasing assumptions and still be suitable for low-level programming if they make a reasonable effort to recognize common aliasing patterns. Some compiler writers are very highly invested in a view of code which fits neither common low-level coding patterns, nor the C Standard, but anyone writing low-level code should simply recognize that those compilers' optimizers are unsuitable for use with low-level code.

Answer 2

The wording of the standard is actually a bit more weird than the actual compiler implementations: The C standard talks about declared object types, but the compilers only ever see pointers to these objects. As such, when a compiler sees a cast from a char* to an unsigned long*, it has to assume that the char* is actually aliasing an object with a declared type of unsigned long, making the cast correct.

A word of caution: I assume that strlen() is compiled into a library that is later only linked to the rest of the application. As such, the optimizer does not see the use of the function when compiling it, forcing it to assume that the cast to unsigned long* is indeed legit. If you called strlen() with

short myString[] = {0x666f, 0x6f00, 0};
size_t length = strlen((char*)myString);    //implementation now invokes undefined behavior!

the cast within strlen() is undefined behavior, and your compiler would be allowed to strip pretty much the entire body of strlen() if it saw your use while compiling strlen() itself. The only thing that allows strlen() to behave as expected in this call is the fact, that strlen() is compiled separately as a library, hiding the undefined behavior from the optimizer, so the optimizer has to assume the cast to be legit when compiling strlen().

So, assuming that the optimizer cannot call "undefined behavior", the reason why casts from char* to anything else are dangerous, is not aliasing, but alignment. On some hardware, weird stuff starts happening if you try to access a misaligned pointer. The hardware might load data from the wrong address, raise an interrupt, or just process the requested memory load extremely slowly. That is why the C standard generally declares such casts undefined behavior.

Nevertheless, you see that the code in question actually handles the alignment issue explicitly (the first loop that contains the (unsigned long int) char_ptr & (sizeof (longword) - 1) subcondition). After that, the char* is properly aligned to be reinterpreted as unsigned long*.

Of course, all of this is not really compliant with the C standard, but it is compliant with the C implementation of the compiler that this code is meant to be compiled with. If the gcc people modified their compiler to act up on this bit of code, the glibc people would just complain about it loud enough so that the gcc will be changed back to handle this kind of cast correctly.

At the end of the day, standard C library implementations simply must violate strict aliasing rules to work properly and be efficient. strlen() just needs to violate those rules to be efficient, the malloc()/free() function pair must be able to take a memory region that had a declared type of Foo, and turn it into a memory region of declared type Bar. And there is no malloc() call inside the malloc() implementation that would give the object a declared type in the first place. The abstraction of the C language simply breaks down at this level.

Answer 3

The underlying assumption is probably that the function is separately compiled, and not available for inlining or other cross function optimizations. This means that no compile time information flows inside or outside the function.

The function doesn't try to modify anything through a pointer, so there is no conflict.

Answer 4

In ISO C this code would violate the strict aliasing rule. (And also violate the rule that you cannot define a function with the same name as a standard library function). However this code is not subject to the rules of ISO C. The standard library doesn't even have to be implemented in a C-like language. The standard only specifies that the implementation implements the behaviour of the standard functions.

In this case, we could say that the implementation is in a C-like GNU dialect, and if the code is compiled with the writer's intended compiler and settings then it would implement the standard library function successfully.