CODEWITHSUNDEEP
parsinggoline
tseries
tseries

Reputation: 783

How remove \n from lines

file, _ := os.Open("x.txt")
f := bufio.NewReader(file)

for {
    read_line, _ := ReadString('\n')
    fmt.Print(read_line)

    // other code what work with parsed line...
}

End it add \n on every line , end program to work , only work with last line...

Please put example, I try anything end any solution what i find here not work for me.

Upvotes: 57

Views: 124624

Answers (3)

Ayush Kumar
Ayush Kumar

Reputation: 954

Clean and Simple Approach

You can also use the strings.TrimSpace() function which will also remove any extra trailing or leading characters like the ones of regex \n, \r and this approach is much more cleaner.

read_line = strings.TrimSpace(read_line)

Go doc: https://pkg.go.dev/strings#TrimSpace

Upvotes: 20

putu
putu

Reputation: 6454

If you want to read a file line-by-line, using bufio.Scanner will be easier. Scanner won't includes endline (\n or \r\n) into the line.

file, err := os.Open("yourfile.txt")
if err != nil {
    //handle error
    return
}
defer file.Close()

s := bufio.NewScanner(file)
for s.Scan() {
    read_line := s.Text()

    // other code what work with parsed line...
}

If you want to remove endline, I suggest you to use TrimRightFunc, i.e.

read_line = strings.TrimRightFunc(read_line, func(c rune) bool {
    //In windows newline is \r\n
    return c == '\r' || c == '\n'
})

Update:
As pointed by @GwynethLlewelyn, using TrimRight will be simpler (cleaner), i.e.

 read_line = strings.TrimRight(read_line, "\r\n")

Internally, TrimRight function call TrimRightFunc, and will remove the character if it match any character given as the second argument of TrimRight.

Upvotes: 25

Alex Lew
Alex Lew

Reputation: 2124

You can slice off the last character:

read_line = read_line[:len(read_line)-1]

Perhaps a better approach is to use the strings library:

read_line = strings.TrimSuffix(read_line, "\n")

Upvotes: 85

Related Questions