CODEWITHSUNDEEP
iosobjective-cjson
user7261225
user7261225

Reputation:

How to get JSON output as NSString

Working in Objective-C where I need to parse JSON. So after parsing successfully.

Below is my code :

-(instancetype)initWithDict:(NSDictionary *)dict {
    self = [super init];
    if (self) {

        if ([dict isKindOfClass:[NSDictionary class]]) {
            self.allKeysArray = [dict allKeys];

 if ([self.allKeysArray containsObject:@"nDetail"]) {

                if ([dict valueForKey:@"nDetail"]) {

 _tempNutrientArray = [[[dict valueForKey:@"nDetail"] valueForKey:@"nTypeCode"] valueForKey:@"value"];
         }
     }
 }

NSLog(@"N Array : @%@", _tempNutrientArray);

}

I need to convert this in string format each an every value.

My output : 

N Array : @(
    "ENER-",
    FAT,
    FASAT,
    CHOAVL,
    "SUGAR-",
    "PRO-",
    NACL
)

Required Output : 

 N Array : @("ENER-","FAT","FASAT","CHOAVL","SUGAR-","PRO-","NACL")

So how should I convert it to string format. Please help me.

Upvotes: 0

Views: 104

Answers (4)

KTang
KTang

Reputation: 350

As the required output you need, you can try:

-(instancetype)initWithDict:(NSDictionary *)dict {
    self = [super init];
    if (self) {

        if ([dict isKindOfClass:[NSDictionary class]]) {
            self.allKeysArray = [dict allKeys];

 if ([self.allKeysArray containsObject:@"nDetail"]) {

                if ([dict valueForKey:@"nDetail"]) {

 _tempNutrientArray = [[[dict valueForKey:@"nDetail"] valueForKey:@"nTypeCode"] valueForKey:@"value"];
         }
     }
 }

NSString *finalString = @"";
[_tempNutrientArray enumerateObjectsUsingBlock:^(id  _Nonnull obj, NSUInteger idx, BOOL * _Nonnull stop) {
    NSString *plainstr = [NSString stringWithFormat:@"%@",obj];
    if (plainstr)
        finalString = [finalString stringByAppendingString:plainstr];
}];

NSLog(@"N Array : @%@", finalString);

}

Upvotes: 0

Himanshu Moradiya
Himanshu Moradiya

Reputation: 4815

In your case you have create one variable that store your whole string from your response after that use my code.

 NSString *tempstring = @"ENER- FAT FASAT CHOAVL SUGAR- PRO- NACL";
 NSArray *arr = [tempstring componentsSeparatedByString:@" "];
 NSLog(@"%@",arr);
 NSLog(@"First value : %@",[arr objectAtIndex:0]);
 NSLog(@"Second value : %@",[arr objectAtIndex:1]);
 NSLog(@"Third value : %@",[arr objectAtIndex:2]);

now check arr value you got all string in array that you want .

Output :

(
    "ENER-",
    FAT,
    FASAT,
    CHOAVL,
    "SUGAR-",
    "PRO-",
    NACL
)

First value : ENER-
Second value : FAT
Third value : FASAT

Upvotes: 0

Esha
Esha

Reputation: 1303

You need to enumerate the whole array to make all object as a proper string. This may be fast operation.

you can use this code:

NSArray *arr = [NSArray arrayWithObjects:@"",@"", nil];
NSMutableArray *arrNew = [NSMutableArray new];

[arr enumerateObjectsUsingBlock:^(id  _Nonnull obj, NSUInteger idx, BOOL * _Nonnull stop) {
    NSString *plainstr = [NSString stringWithFormat:@"%@",obj];
    [arrNew addObject:plainstr];
}];

The arrNew will be the array with string..

Better you convert it to string when you are fetching it.

Upvotes: 1

Bala
Bala

Reputation: 1304

Converting Array to String 

NSString * myString = [_tempNutrientArray componentsJoinedByString:@""];

If you want any Character between the string give it in componentsJoinedByString:@"GIVE_IT_HERE"

Upvotes: 0

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