CODEWITHSUNDEEP
javascriptregex
Nazmul Hasan
Nazmul Hasan

Reputation: 7040

JavaScript regex for checking number have % sign or not

I have a input field, whether i want to input percent value or flat amount for this i have to check it has ends with % sign or not.

sample input may be 

12%
12.888%
12.00%
12.00001%
12.123344%

or for flat amount

100
100.55252
100.254575

something like this.

N.B: I want to learn javascript regex ...have any suggestions?

Upvotes: 3

Views: 14241

Answers (4)

rvbyron
rvbyron

Reputation: 179

All of the previous suggestions are excellent. Depending on your needs, you can choose any of them. I added a bit more to the following to break out the value for you. Modify to suit your needs.

function getValue(num) {
   var matches=num.match(/(^\s*\d+\.?\d*)(%)?\s*$/);
   var m = false, p = false, v = 0;
   if (matches) {
      m = true;
      p = (matches[2]=="%");
      v = matches[1];
   }
   return {isMatch: m, isPercent: p, value: v};
}

var vals = "12%,12.888%,12.00%,12.00001%,12.123344%,100,100.,100.55252,100.254575,notnum".split(',');
for(var i=0;i<vals.length;i++) {
   var gv = getValue(vals[i]);
   console.log("string="+vals[i],"  isMatch="+gv.isMatch,"  isPercent="+gv.isPercent,"  value="+gv.value);
}

Output is:

string=12% isMatch=true isPercent=true value=12
string=12.888% isMatch=true isPercent=true value=12.888
string=12.00% isMatch=true isPercent=true value=12.00
string=12.00001% isMatch=true isPercent=true value=12.00001
string=12.123344% isMatch=true isPercent=true value=12.123344
string=100 isMatch=true isPercent=false value=100
string=100. isMatch=true isPercent=false value=100.
string=100.55252 isMatch=true isPercent=false value=100.55252
string=100.254575 isMatch=true isPercent=false value=100.254575
string=notnum isMatch=false isPercent=false value=0

Upvotes: 2

Sahil Muthoo
Sahil Muthoo

Reputation: 12496

As Anon has already suggested, you don't really need to use Regular Expressions to solve this problem. What's wrong with:

var number = "12.888%";
if(number[number.length - 1] === '%') {
  //processing...
}

Upvotes: 1

dheerosaur
dheerosaur

Reputation: 15172

jQuery uses JavaScript regular expressions. This is a good starting point https://developer.mozilla.org/en/JavaScript/Guide/Regular_Expressions

For your need, /[0-9]*\.?[0-9]+%/ will be useful.

Upvotes: 5

sioked
sioked

Reputation: 226

/%$/.test( "35%" ); >> true
/%$/.test( "100" ); >> false
/%$/.test( "35.555%" ); >> true
/%$/.test( "35.555" );  >> false

Take a look at Mozilla Developer Network for some more info: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/RegExp

Upvotes: 2

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