CODEWITHSUNDEEP
pythonflaskflask-sqlalchemy
Will Scott
Will Scott

Reputation: 77

Flask route not found

I am building a catalog app using flask and sqlalchemy but one of my routes is giving a 404 and I'm not sure why. Here is the code for the route and function:

@app.route('/Category/<string:category_name>/Item/new', methods=['GET', 'POST'])
def newItem(category_name):
    user = getUser()
    if user is None:
        return redirect('/login')
    if request.method == 'POST':
        newItem = Category(name=request.form['name'],
        description=request.form['description'], creator=session['username'],
        category_id=db.query(Category.id).filter_by(category_name=category_name).all())
        db.add(newItem)
        db.commit()
        return redirect(url_for('showCategory(category_name)'))
    else:
        return render_template('newItem.html', categories=categories)

The newItem.html template does exist in the template folder, and using another route I have for viewing an item: @app.route('/Category/<string:category_name>/Item/<string:item_name> works so category_name is being defined. The url I'm going to is https://localhost:5000/Category/Sports/Item/new and Sports is a category in the database, I cannot figure out why I'm getting the 404

Traceback (shows trying to enter showItem route not newItem route):enter image description here

Upvotes: 0

Views: 2730

Answers (2)

Paul Becotte
Paul Becotte

Reputation: 9977

Your URL rules are hitting the wrong function...

@app.route('/Category/<string:category_name>/Item/<string:item_name> happens to match https://localhost:5000/Category/Sports/Item/new

You need to add an extra segment to the first one like @app.route('/Category/<string:category_name>/Item/existing/<string:item_name>

Upvotes: 2

Dmitry Belaventsev
Dmitry Belaventsev

Reputation: 6657

You're getting sqlalchemy.orm.exc.NoResultFound exception. It means that view function was called successfully, but now data could be found.

Upvotes: 0

Related Questions