CODEWITHSUNDEEP
python
user5411744
user5411744

Reputation:

Returning a list from longest string length to shortest string length

What is a good way to add elements to a list that automatically adds elements depending on their string length?

For example.

class MyQueueSystem():

    def __init__(self, myfunction):
self.myfucntion = myfunction
        self.data = []



    def add(self, item):
        pass

For example,

def shorter(a, b):
    return len(a) < len(b)

>>> me = MyQueueSystem(shorter)
>>> me.add('111')
>>> me.add('11')
>>> me.add('11111')
>>> print (me.data)
['11111','111','11']

item in the add function is an object.

My question is, how do you access a function as a parameter?

edit : I forgot to add a argument in the Init

Upvotes: 1

Views: 80

Answers (1)

Moinuddin Quadri
Moinuddin Quadri

Reputation: 48090

You may use sorted function within your add(..) fucntion to sort the list based on the len. Below is sample structure for your class:

class MyQueueSystem():
    #                    v It should be passed as an argument to `__init__`
    def __init__(self, data):
        self.data = self._sort_on_length(data)

    def add(self, item):
        self.data = self._sort_on_length(self.data+[item])

    def _sort_on_length(self, sort_list):
        """
        Function to sort the argument `list` based on the length
        in the descending order
        """
        return sorted(sort_list, key=lambda x: -len(x))

Sample Run:

>>> my_object = MyQueueSystem(['111', '11', '11111'])
>>> my_object.data
['11111', '111', '11']

>>> my_object.add('1111')
>>> my_object.data
['11111', '1111', '111', '11']

Upvotes: 1

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