CODEWITHSUNDEEP
gorandom
typos
typos

Reputation: 6662

Random 64-bit integer from crypto/rand

I want to generate 64-bit random integer using the secure crypto/rand package. I found this online:

package main

import (
    "crypto/rand"
    "encoding/base64"
)

// GenerateRandomBytes returns securely generated random bytes.
// It will return an error if the system's secure random
// number generator fails to function correctly, in which
// case the caller should not continue.
func GenerateRandomBytes(n int) ([]byte, error) {
    b := make([]byte, n)
    _, err := rand.Read(b)
    // Note that err == nil only if we read len(b) bytes.
    if err != nil {
        return nil, err
    }

    return b, nil
}

But it seems to generate random bytes instead. I want a random 64-bit int. Namely, I want something like var i uint64 = rand(). Any ideas how to achieve this?

Upvotes: 3

Views: 4535

Answers (2)

Kishan B
Kishan B

Reputation: 5375

You also use rand.Int in crypto/rand package

func randint64() (int64, error) {
    val, err := rand.Int(rand.Reader, big.NewInt(int64(math.MaxInt64)))
    if err != nil {
        return 0, err
    }
    return val.Int64(), nil
}

https://play.golang.org/p/fqoQxpmjOSu

Upvotes: 2

user142162
user142162

Reputation:

You can generate a random number with crypto.Rand, and then convert those bytes to an int64 using the binary package:

func randint64() (int64, error) {
    var b [8]byte
    if _, err := rand.Read(b[:]); err != nil {
        return 0, err
    }
    return int64(binary.LittleEndian.Uint64(b[:])), nil
}

https://play.golang.org/p/2Q8tvttqbJ (result is cached)

If you look at the source code for LittleEndian.Uint64, you can see it's simply performing a few bit operations on the data; something that you could implemented for yourself.

Upvotes: 3

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