CODEWITHSUNDEEP
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CommonSenseCode
CommonSenseCode

Reputation: 25369

MacOSX terminal which git return error: zsh: bad option: -l

I have noticed some problems lately on my git and I want to uninstall it, when I try to identify the path with:

  which git

I always get the following error:

zsh: bad option: -l

any ideas what this error might be indicating?

I have tried on iterm and on default terminal but get always the same error.

Upvotes: 3

Views: 3010

Answers (3)

heartunicyclist
heartunicyclist

Reputation: 323

Also had this issue. I found using the command whereis in place of whichseemed to work just as well for me.

Based on this answer.

Upvotes: 0

Dan Bitter
Dan Bitter

Reputation: 259

In my case, I was having trouble getting sdkman to work and seeing this:

danbitter@Dans-MBP ~ % source "/Users/danbitter/.sdkman/bin/sdkman-init.sh"
find: -type: open: unknown type
/Users/danbitter/.sdkman/bin/sdkman-init.sh:83: parse error near `-a'

Thanks to @marc0der & @helpermethod, the issue was in my .zshrc file:

alias -g f='open -a Finder ./' # f: Opens current directory in MacOS Finder

This is super weird because disabling that line in the .zshrc file allows sdkman to function in the zsh shell. But, I can then paste the actual command open -a Finder ./ in that same zsh shell and it opens a Finder in the working directory? Color me confused ¯\(ツ)/¯

edit: I changed it from an alias -g to a function f() {open .;} and now my .zshrc works happily alongside sdkman :-)

Upvotes: 0

Zooly
Zooly

Reputation: 4787

Check if your .bashrc or .bash_profile (maybe .zshrc) has an alias on which command.

Upvotes: 5

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