CODEWITHSUNDEEP
java
Vidhyasagar Vasis
Vidhyasagar Vasis

Reputation: 33

Getting list data as string in java

I have a list of data in the iterator.I want to store it in a string. How can I do it? Here is my code.

List ln = readData(iStepNumber, status, query);

Iterator itr = ln.iterator();

System.out.println("listttt"+ln);

while(itr.hasNext()) {
    System.out.println("itr value1 :"+itr.next());
    //what to do to store itr.next() in a string
    //for example String a=itr.next()?
}

This is what I get in the console

listttt[2017-06-30 23:59:59]
itr value1 :2017-06-30 23:59:59

Upvotes: 0

Views: 142

Answers (4)

Pavan
Pavan

Reputation: 113

You can use Java 8 stream API.
Take your list of respective object type

List<Object> ln = readData(iStepNumber, status, query);
Iterator itr = ln.iterator();
System.out.println("listttt"+ln);

// Now call the stream() method on list 

 String data=ln.stream()  
               .map(Object::toString)  
               .collect(Collectors.joining(","));

// Here use whatever you want as string in joining method string and print 
// or do what ever you want with string data.

System.out.println(data);

Upvotes: 0

kk.
kk.

Reputation: 3945

Just implement toString() method in your object and output the list using System.out.println(list). This will display all the data without any need of iteration manually in your code.

Upvotes: 0

Ramon Marques
Ramon Marques

Reputation: 3264

You should use stringbuffer

List ln = readData(iStepNumber, status, query);
Iterator itr = ln.iterator();
System.out.println("listttt"+ln);

StringBuffer sBuffer = new StringBuffer();

while(itr.hasNext()){
  sBuffer.append(itr.next());
  System.out.println("itr value1 :"+itr.next());
}

Upvotes: 1

josephmbustamante
josephmbustamante

Reputation: 352

Instead of just printing itr.next(), save it to a string variable like this:

String yourString = itr.next();

If you have more than one item in the list, you can either do yourString += itr.next(), or use a StringBuilder and StringBuilder.append(), which is much more efficient.

Upvotes: 2

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