CODEWITHSUNDEEP
c++
CurtisJC
CurtisJC

Reputation: 690

Creating my own 'data type'

I want to be able to create a type that has 3 floats (x,y,z). I have tried:

typedef struct
{
 float x;
 float y;
 float z;
} Vertex;

But that didn't work.

Does this have to be declared somewhere where it can be seen by main? How would I go about creating getter methods and other methods for a type I have made?

Upvotes: 3

Views: 24344

Answers (3)

PeteUK
PeteUK

Reputation: 1112

How I'd do it in C++. See main() for example usage. N.B. This hasn't been compiled or tested.

#include <iostream>

class Vertex
{
public:
  // Construction
  Vertex(float x,float y, float z) : x_(x), y_(y), z_(z) {}

  // Getters
  float getX() const {return x_;}
  float getY() const {return y_;}
  float getZ() const {return z_;}

  // Setters
  void setX(float val) {x_ = val;}
  void setY(float val) {y_ = val;}
  void setZ(float val) {z_ = val;}
private:
  float x_;
  float y_;
  float z_;
};

int main()
{
  Vertex v(6.0f,7.2f,3.3f);
  v.setZ(7.7f);
  std::cout < "vertex components are " << v.getX() << ',' << v.getY() << ',' << v.getZ() << std::endl;
}

Upvotes: 5

pmg
pmg

Reputation: 108978

Using C, this works for me

typedef struct { float x; float y; float z; } Vertex;

int main(void) {
  Vertex a = {42, -42, 0};
  if (a.x + a.y + a.z == 0) return 1; /* warning about comparing floating point values */
  return 0;
}

Upvotes: 1

John Dibling
John Dibling

Reputation: 101456

does this have to be declared somewhere where it can be seen by main?

Yes. Typically the class or struct is declared in a header file, which you #include in whatever translation unit (c file) you use it in.

Upvotes: 1

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