Reputation: 223
I have the following dictionary
{
"b3e0aded-d57b-4159-9c33-c8b006282334" : {
"57646099-b717-4a2b-b9eb-2935548ae954" : [
"yes"
]
},
"1b186bc7-52c4-4b87-a97f-cc52054aad24" : {
"aba16653-bda0-4e89-b1c8-63df6faa7c10" : [
"yes"
]
},
"d765038e-e85a-495d-9932-170852fbd86e" : {
"aba16653-bda0-4e89-b1c8-63df6faa7c10" : [
"yes"
],
"57646099-b717-4a2b-b9eb-2935548ae954" : [
"yes"
],
"957bdaba-b23d-4243-8384-62dfa46f0656" : "play"
},
"2a8dd370-2f7e-4c8e-93d5-21102fbc82fd" : {
"aba16653-bda0-4e89-b1c8-63df6faa7c10" : [
"yes"
]
}
}
How to get each object say "b3e0aded-d57b-4159-9c33-c8b006282334" : { "57646099-b717-4a2b-b9eb-2935548ae954" : [ "yes" ] }
OR "d765038e-e85a-495d-9932-170852fbd86e" : { "aba16653-bda0-4e89-b1c8-63df6faa7c10" : [ "yes" ], "57646099-b717-4a2b-b9eb-2935548ae954" : [ "yes" ]
from this NSDictionary?
Upvotes: 0
Views: 250
Reputation: 722
use for each in loop to get the full value. i.e
let dict = your dictionary
for each in dict {
print(each)
}
Upvotes: 2
Reputation: 567
You can use objectForKey:
to read the value for a key:
id value = [dict objectForKey:@"b3e0aded-d57b-4159-9c33-c8b006282334"]
Which can be expressed more concisely using square bracket notation:
id value = dict[@"b3e0aded-d57b-4159-9c33-c8b006282334"]
If you then want an object containing just that key mapped to its value then the easiest thing to do is just to construct a new object with the key and value:
id key = @"b3e0aded-d57b-4159-9c33-c8b006282334";
id value = dict[key];
id result = @{ key: value }
Upvotes: 1